3 years ago

What are the following solutions to 2x^2-8x-90

Mathematics

1 answer:

Nostrana [21]3 years ago

7 0

You're 2 solutions are

(9,0)(-5,0)

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A company manufactures penny number 2 nails that are 1 inch in length. The actual length is allowed to vary by up to \displaysty

Diano4ka-milaya [45]

The absolute value equation representing the length of the nail is :

$\frac{31}{32} \leqslant x \leqslant 1 \frac{1}{32}$

A nail of length 1.05 inches is unacceptable

Actual Length of nail = 1 inch

Allowable variation = 1/32 inches

The minimum allowable length :

actual length - allowable variation

$1 - \frac{1}{32} = \frac{31}{32}$

The maximum allowable length :

Actual length + allowable variation

$1 + \frac{1}{32} = 1 \frac{1}{32}$

The length of X, of the nail must be follow the equation :

Minimum ≤ X ≤ maximum

$\frac{31}{32} \leqslant x \leqslant 1 \frac{1}{32}$

A nail of length 1.05 inches

Maximum nail length = 1 1/32 = 1.031

1.05 > 1.031 ; hence, it is greater than the maximum allowable length and hence, Unacceptabe

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S = vt + 16t^2, solve for v.

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