Answer:
46°
Step-by-step explanation:
When secants intersect each other and a circle, the external angle (A) is half the difference of the intercepted arcs:
∠A = (arcDC -arcBC)/2
12° = (arcDC -22°)/2 . . . . . . . fill in the given numbers
24° = arcDC -22° . . . . . . . . . multiply by 2
46° = arcDC . . . . . . . . . . . . . add 22°
Answer:
24
Step-by-step explanation:
I think there the same for each but I hope I helped
Well basically you just have to chose a number of sides for the side length of the square to be and move those many places to get another vertex of the square. For example if we have (-2,3) and we choose the side lengths to be 4 units than you could move 4 places up, down, left, or right to get the other vertices for the square
Hope that helps :)
The answer is a = 3/4 = 0.75
First get rid of the paranthesis,

Then set the denominators equal:

Then remove the denominators and solve:

Eliminate -12a^2 by adding 12a^2 to both sides:

Take the fourth root of them or take the square root twice:
![\sqrt[4]{256 {a}^{4} } = \sqrt[4]{81} \\ 4a = 3](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B256%20%7Ba%7D%5E%7B4%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B81%7D%20%20%20%5C%5C%20%204a%20%3D%203)
Divide both sides by 4:
The answer would be B. As you can see Angle A and angle B are connected by that line and together they would equal 90 degrees like on the other side of line AB.