At t=0, a rock is dropped from rest from the top of a building 256 ft high. With what velocity will it strike the ground? What i
s it acceleration
1 answer:
Answer:
128 ft / second.
Step-by-step explanation:
It's acceleration is due to gravity and is 32 ft s^-2.
To find the velocity when it hits the ground we use the equation of motion
v^2 = u^2 + 2gs where u = initial velocity, g = acceleration , s = distance.
v^2 = 0^2 + 2 * 32 * 256
v^2 = 16384
v = 128 ft s^-1.
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