Here is a sample problem
has to be perpendicular to y=(4/9)*x-2 and pass through 4,3,

y-b=m(x-a)
slope of -9/4 is perpendicular to slope of 4/9, as y=4/9x-2 has slope 4/9. Our point is (4,3) therefore.
y-3=-9/4*(x-4)
y-3=-9/4x+9
y=-9/4x+9+3
y=-9/4x+12

5 0

2 years ago

Question 3, help please!

White raven [17]

The answer is not defined.

Explanation:

The given matrix is $\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]+\left[\begin{array}{c}{1} \\ {0}\end{array}\right]$

The matrix $\left[\begin{array}{cc}{2} & {4} \\ {1} & {-6}\end{array}\right]$ has dimensions $2\times 2$

This means that the matrix has 2 rows and 2 columns.

Also, the matrix $\left[\begin{array}{l}{1} \\ {0}\end{array}\right]$ has dimensions $2\times1$

This means that the matrix has 2 rows and 1 column.

Since, the matrices can be added only if they have the same dimensions.

In other words, to add the matrices, the two matrices must have the same number of rows and same number of columns.

Since, the dimensions of the two matrices are not equal, the addition of these two matrices is not possible.

Hence, the addition of these two matrices is not defined.

4 0

3 years ago

Marcus is 5 19/24 feet tall. Ben is 5 9/16 feet tall. Which of the two boys is taller?

Ksju [112]

well, Marcus and Ben are both 5 feet tall and a little bit more, Marcus is 19/24 more and Ben is 9/16 more, so the 5's in the fraction are the same, so which one is larger, 19/24 or 9/16?

we can simply put both fractions with the same denominator, by <u>multiplying one by the other's denominator</u>, so let's proceed,

$\bf \stackrel{\textit{\large Marcus is taller}}{5~feet + \left( \cfrac{19}{24}\cdot \cfrac{16}{16}\implies \boxed{\cfrac{304}{384}} \right)}\qquad \qquad \qquad \stackrel{\textit{\large Ben}}{5~feet + \left( \cfrac{9}{16}\cdot \cfrac{24}{24}\implies \boxed{\cfrac{216}{384}} \right)}$

4 0

3 years ago