Think of the two pieces together as a single cone of height 19, and its volume.
Then think of only the upper piece as a cone, and find its volume.
The volume of the frustum is the total volume minus the volume of the upper piece.
The volume of a cone is:
Total volume:
Volume of upper cone:
Volume of frustum:
(f-g)(x) = f(x) - g(x)
= (x^3 -2x+6) - (2x^3+3x^2-4x+2)
= x^3 -2x +6 -2x^3 -3x^2 +4x -2 . . . . distribute the negative sign
= (1-2)x^3 -3x^2 +(-2+4)x +(6-2) . . . . . combine like terms
(f-g)(x) = -x^3 -3x^2 +2x +4
Answer:
6m
Step-by-step explanation:
h=3(/V
πr^2)=3(226/
π·6^2)≈5.99484
round to 6
Answer:
1/216
Step-by-step explanation:
I am pretty sure this is correct
you have to make the whole number 6 into a fraction 6/1
now it is 1/6 divided by 6/1 but you need to do KCF keep change flip
so now it is 1/6 times 1/6 and you get 1/36
then turn 6 into a fraction again
then KCF
Now it is 1/36 times 1/6 and you get 1/216
-3/4x + 5/6 y = 15
Multiply through by 6
-9/2x + 5y = 90
Add 9/2x to both sides
5y = 90 + 9/2x
Divide both sides by 5
y = 18 + 9/10x
y = 9/10x + 18
Comparing with the general equation of a straight line y = mx + c
Gradient (m) = 9/10 or 0.9
and the y - intercept (c) = 18
