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bixtya [17]
3 years ago
13

Write in simplest form. 1/6 divided by 6 divided by 6

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
7 0

Answer:

1/216

Step-by-step explanation:

I am pretty sure this is correct

you have to make the whole number 6 into a fraction 6/1

now it is 1/6 divided by 6/1 but you need to do KCF keep change flip

so now it is 1/6 times 1/6 and you get 1/36

then turn 6 into a fraction again

then KCF

Now it is 1/36 times 1/6 and you get 1/216

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Which are the center and radius of the circle with equation (x + 5)2 + (y - 4)2 = 9?
alina1380 [7]

Answer:

Center (-5,4) radius 3

Step-by-step explanation:

The standard equation of a circle is

(x-h)^2+(y-k)^2=r^2

where the center is (h,k) and r is the radius

so h=-5 in this case and k is 4

r^2=9 so r=3

4 0
3 years ago
Please help me out The equation 9(w + 7) = 27 solved in several steps below. For each step, choose the reason that best justifie
Vaselesa [24]
9w+63=27

27-63= -36

-36•/•9=-4

answer: -4=w

hope this helps
4 0
3 years ago
ACTIVITY 2 (19) Mr Duma recently inherited a rectangular plot, part of the estate left by his late father. The plot with the fol
seraphim [82]

The sum of the lengths of three sides of the rectangle, gives the length

of the fencing, while one third of the rectangle area is for the pavement.

Responses:

Project A: The formula for the length of the fencing is, L = 4·x - 1

Project B: Length of the fancy wall = 2·x + 1

Project \ C:Area \ of \ the \ paving = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3}  - \dfrac{1}{3}}

<h3>Which method can be used to find the length and area of paving from the given equations?</h3>

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Given parameters are;

Length of the rectangular plot = 2·x + 1

Width of the rectangular plot = x - 1

Vertices of the rectangular plot are; QPSR

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Which gives;

SP = QR = x - 1

The length of the fencing, L = SP + PQ + QR = x - 1 + 2·x + 1 + x - 1 = 4·x - 1

  • The formula for the length of the fencing is, L =<u> 4·x - 1</u>

Project B: The front side is SR

Therefore;

  • Length of the fancy wall = <u>2·x + 1</u>

Project C:

Area, A = Length × Width

Area of the plot, A = (2·x + 1) × (x - 1) = 2·x² - x - 1

  • Area \ of \ the \ paving = \dfrac{1}{3} \times \left(2 \cdot x^2 - x - 1\right) = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3}  - \dfrac{1}{3}}

Learn more about writing equations here:

brainly.com/question/24760633

6 0
2 years ago
6x − 5 = 5(x − 3) + x<br> X=???
Fudgin [204]

Answer:No solution

Step-by-step explanation:

8 0
2 years ago
2x+3y=19 // 6x+2y=22​
zvonat [6]

Answer:

(2, 5 )

Step-by-step explanation:

Given the 2 equations

2x + 3y = 19 → (1)

6x + 2y = 22 → (2)

Multiplying (1) by - 3 and adding to (2) will eliminate the x- term

- 6x - 9y = - 57 → (3)

Add (2) and (3) term by term to eliminate x

0 - 7y = - 35

- 7y = - 35 ( divide both sides by - 7 )

y = 5

Substitute y = 5 into either of the 2 equations and solve for x

Substituting into (1)

2x + 3(5) = 19

2x + 15 = 19 ( subtract 15 from both sides )

2x = 4 ( divide both sides by 2 )

x = 2

solution is (2, 5 )

7 0
3 years ago
Read 2 more answers
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