pls help me......................................................................................................

Mathematics

2 answers:

Gemiola [76]2 years ago

8 0

Answer:

The first one is y=2, the second y=3

Step-by-step explanation:

Feliz [49]2 years ago

6 0

What she said, it’s right

You might be interested in

Find the solution of 3 times the square root of the quantity of x plus 6 equals negative 12, and determine if it is an extraneou

Anna35 [415]

For this case we have the following equation:
$3 \sqrt{x+6}=-12$
Rewriting we have:
$\sqrt{x+6}= \frac{-12}{3}$
$\sqrt{x+6}=-4$
We raise both members of the equation to the square:
$(\sqrt{x+6})^2=(-4)^2$
Rewriting we have:
$x+6=16$
$x=16-6$
$x=10$
It's a extraneous solution because equality is not met by substituting x = 10 in the original equation:
$3 \sqrt{10+6}=-12$
$3 \sqrt{16}=-12$
$3(4)=-12$
$12=-12$
Answer:
The solution is:
$x=10$
It's a extraneous solution

6 0

3 years ago

Is 0 an integer ? It wont let me post without making it longer

lina2011 [118]

Yes, it is. You may prove it using something like this: 1 is an integer. 1-1 is a difference between integers. A difference between integers returns an integer, so 0 is an integer.

7 0

2 years ago

Help pls also show work if needed!

neonofarm [45]

Answer AND Step-by-step explanation:

Everything is in the picture.

#teamtrees #PAW (Plant And Water)

The equation is:

$c = -\frac{1}{2} t + 6$