∠13 = 70.5° [Vertically Opposite angles]
∠13+∠14=180° [Linear pair]
70.5°+∠14=180°
∠14=180-70.5
∠14=109.5
∠15=∠14=109.5 [Vertically opposite angles]
∠13=∠12= 70.5° [Co-interior angles]
∠12=∠10= 70.5° [Vertically Opposite angles]
∠14=∠11=109.5 [Co-interior angles]
∠9=∠11= 109.5 [Vertically opposite angles]
∠13=∠7= 70.5° [Alternate interior angles]
∠7=∠5=70.5° [Vertically Opposite angles]
∠7+∠8=180° [Linear Pair]
70.5+∠8=180
∠8=180-70.5
∠8=109.5°
∠8=∠6= 109.5° [Vertically Opposite angles]
∠6=∠3=109.5° [Co-interior angles]
∠7=∠2=70.5° [Co-exterior angles]
∠2=∠4= 70.5° [Vertically Opposite angles]
∠3=∠1= 109.5° [Vertically Opposite angles]
<h3>Measures of all angles in sequence⤵️</h3>
- ∠1= 109.5°
- ∠2= 70.5°
- ∠3= 109.5°
- ∠4= 70.5°
- ∠5= 70.5°
- ∠6= 109.5°
- ∠7= 70.5°
- ∠8= 109.5°
- ∠9= 109.5°
- ∠10= 109.5°
- ∠11= 70.5°
- ∠12= 109.5°
- ∠13= 70.5°
- ∠14= 109.5°
- ∠15= 109.5°
- ∠16= 70.5°
Answer:
18 minutes
Step-by-step explanation:
Answer:
x³+y³+z³=k , k from 1 to 100. To Find : x, y, and z. Solution: This Question can have lot of solutions as constraints are very less.
A=number of adult tickets
s=number of student tickets
so
total of 89 tickets sold
a+s=89
total collected was 1119
15a+11s=1119
so we have
a+s=89
15a+11s=1119
subsitution
a+s=89
minus s from both sides
a=89-s
subsitte 89-s for a in the other equation
15a-11s=1119
15(89-s)+11s=1119
1335-15s+11s=1119
1335-4s=1119
minus 1335 from both sides
-4s=-216
divide both sides by -4
s=54
subsitute back
a=89-s
a=89-54
a=35
35 adult tickets
54 student tickets
Answer:
2. Like terms: 5a 4. Lt: 4y, and y
coefficient: 2,-7 coefficient: 4, -3
Constant: 2,-7 constant: 4
3. like terms: 3h, 2h, and 6h can you follow these and do the remaining??
if no, I'll help u
coefficient: 3,2,6
constant: 9