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Marina86 [1]
3 years ago
12

SOLVE. 70 = -2.5xneed this asap

Mathematics
1 answer:
nalin [4]3 years ago
4 0

Answer:

-28

Step-by-step explanation:

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ANEK [815]

Answer: c=24

Step-by-step explanation: 15×3=45. 8×3=24. Just multiply both the numerator and denominator by 3.

5 0
3 years ago
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20% of US High School teens vape. A local High School has implemented campaigns to reduce vaping among students and believes tha
zaharov [31]

Answer:

10.93% probability of observing 51 or fewer vapers in a random sample of 300

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 300, p = 0.2

So

\mu = E(X) = np = 300*0.2 = 60

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.2*0.8} = 6.9282

What is the approximate probability of observing 51 or fewer vapers in a random sample of 300?

Using continuity corrections, this is P(X \leq 51 + 0.5) = P(X \leq 51.5), which is the pvalue of Z when X = 51.5 So

Z = \frac{X - \mu}{\sigma}

Z = \frac{51.5 - 60}{6.9282}

Z = -1.23

Z = -1.23 has a pvalue of 0.1093.

10.93% probability of observing 51 or fewer vapers in a random sample of 300

4 0
3 years ago
I got the answer it is A I just need you to check it pls thank you
andrey2020 [161]

We have a circle of radius 5 m inside a square of side 10 m. The shaded area is:

A_{\text{Shaded}}=A_{\text{Square}}-A_{\text{Circle}}

Now, we calculate the area of the square and the circle:

\begin{gathered} A_{\text{Square}}=10^2=100m^2 \\ A_{\text{Circle}}=\pi\cdot5^2=25\pi m^2 \end{gathered}

Finally, the shaded area is:

A_{\text{Shaded}}=100-25\pi\approx21.5m^2

3 0
10 months ago
How to solve??????????HELP
nadezda [96]

I presume you're talking about number 3?

Solution

I = prt (I being the interest)

I =

5000 \times 5 \times.05

I = 1,250$

3 0
2 years ago
Please help! It would be greatly appreciated please tysm 20 points multiple questions
Firlakuza [10]

Answer:

COD, BC, intersecting

Step-by-step explanation:

7 0
3 years ago
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