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Marina86 [1]
3 years ago
12

SOLVE. 70 = -2.5xneed this asap

Mathematics
1 answer:
nalin [4]3 years ago
4 0

Answer:

-28

Step-by-step explanation:

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Can someone please help me on this one!!!!
VashaNatasha [74]
This appears to be about rules of exponents as much as anything. The applicable "definitions, identities, and properties" are
  i^0 = 1 . . . . . as is true for any non-zero value to the zero power
  i^1 = i . . . . . . as is true for any value to the first power
  i^2 = -1 . . . . . from the definition of i
  i^3 = -i . . . . . = (i^2)·(i^1) = -1·i = -i
  i^n = i^(n mod 4) . . . . . where "n mod 4" is the remainder after division by 4


1. = -3^4·i^(3·2+0+2·4) = -81·i^14 = 81

2. = i^((3-5)·2+0 = i^-4 = 1

3. = -2^2·i^(4+2+2+(-1+1+5)·3+0) = -4·i^23 = 4i

4. = i^(3+(2+3+4+0+2+5)·2) = i^35 = -i

5 0
3 years ago
There is a string of red and blue lights strung around a window . The red lights blink every 3 seconds , and the blue lights bli
Nezavi [6.7K]
Give us more evidence please
3 0
3 years ago
Vaimiti walks at a constant pace of 1.1 m/s and takes 25 minutes to get to school.
Temka [501]

Solution:

<u>Note that:</u>

  • Speed = Distance/Time
  • Vaimiti speed = 1.1 m/s
  • Jabril speed = 1.3 m/s

<u>Converting the time (minutes to seconds) for Vaimiti to reach school:</u>

  • Vaimiti's time to reach school: 25 minutes = 25 x 60 seconds
  • => Vaimiti's time to reach school: 1500 seconds

<u>Converting the time (minutes to seconds) for Jabril to reach school:</u>

  • Jabril's time to reach school: 30 minutes = 30 x 60 seconds
  • => Jabril's time to reach school: 1800 seconds

<u>Finding the distance of Vaimiti:</u>

  • Speed = Distance/Time

Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>

  • => 1.1 meters/second = Distance/1500
  • => 1.1 x 1500 = Distance
  • => 1650 meters = Distance (In meters)

<u>Finding the distance of Jabril:</u>

  • Speed = Distance/Time

Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>

  • 1.3 meters/second = Distance (In meters)/1800 seconds
  • => 1.3 x 1800 = Distance (In meters)
  • => 2340 meters = Distance (In meters)

This can lead to two possible solutions:

Possible solution #1:

<u>Finding the difference between the two distances:</u>

  • 2340 meters - 1650 meters = Difference (In meters)
  • => 690 meters

Possible solution #2:

The difference between the <u>distances they walked</u> is that Jabril walked <u>faster</u> than Vaimiti, but Vaimiti reached <u>school</u> earlier than Jabril because the <u>walking distance</u> for Vaimiti is less than the <u>walking</u> <u>distance</u> for Jabril.

Hoped this helped!

6 0
3 years ago
Read 2 more answers
Suppose a random sample of 40 students from a university were asked their ages. The table below gives a summary of the reported
fomenos

Answer:

I think it is

Step-by-step explanation:

(18.0, 22.0). We are 95% confident that the mean age of university students is between 18 and 22.

4 0
2 years ago
Find the possible value or values of y in the quadratic equation z^2 - 4z+ 4 =0
jeyben [28]
Didn't you mean "Find the possible value or values of z?  y is not at all present in this equation.

z^2 - 4z + 4 = 0 can be factored into (z-2)(z-2).  Thus, the given equation has two equal, real solutions:  z=2 and z=-2.
5 0
3 years ago
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