What angle would you use to represent 5 blue cars out of 20 cars in total on a pie chart?

When measuring and recording vital signs, healthcare professionals sometimes have to convert units of measurement, especially wh

nataly862011 [7]

Answer:

116°F = 46.67 °C and 6 Pounds = 2721.55 grams

Step-by-step explanation:

The information given in the question is 1°F = -17.22°C

1 Kilogram = 1000 grams = 2.2 pounds

And we have to convert 116° F to degrees Celsius and Six pounds to grams.

1) We know (°F-32)×5/9 =°C

So by putting the value of °F as 116 ⇒ (116-32)×5÷9 = °C

⇒ °C = $\frac{(84)(5)}{9}$

⇒ °C = 46.67

2). ∵ 2.2 Pounds = 1000 grams

∴1 Pound = 1000/2.2 = 454.54 grams

∴ 6 pounds = 6× 454.54 grams

= 2721.55 grams

4 0

3 years ago

What is the axis of symmetry for the parabola with the equation y=2x^2

Anestetic [448]

The axis of symmetry would be x=0

8 0

3 years ago

If -y-2x^3=Y^2 then find D^2y/dx^2 at the point (-1,-2) in simplest form

algol13

Answer:

$\frac{d^2y}{dx^2} = \frac{-4}{3}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-y - 2x³ = y²

Rate of change of tangent line at point (-1, -2)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Basic Power Rule]: $-y'-6x^2=2yy'$
[Algebra] Isolate y' terms: $-6x^2=2yy'+y'$
[Algebra] Factor y': $-6x^2=y'(2y+1)$
[Algebra] Isolate y': $\frac{-6x^2}{(2y+1)}=y'$
[Algebra] Rewrite: $y' = \frac{-6x^2}{(2y+1)}$

Step 3: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{-12x(2y+1)+6x^2(2y')}{(2y+1)^2}$
[Derivative] Simplify: $y'' = \frac{-24xy-12x+12x^2y'}{(2y+1)^2}$
[Derivative] Back-Substitute y': $y'' = \frac{-24xy-12x+12x^2(\frac{-6x^2}{2y+1} )}{(2y+1)^2}$
[Derivative] Simplify: $y'' = \frac{-24xy-12x-\frac{72x^4}{2y+1} }{(2y+1)^2}$

Step 4: Find Slope at Given Point

[Algebra] Substitute in x and y: $y''(-1,-2) = \frac{-24(-1)(-2)-12(-1)-\frac{72(-1)^4}{2(-2)+1} }{(2(-2)+1)^2}$
[Pre-Algebra] Exponents: $y''(-1,-2) = \frac{-24(-1)(-2)-12(-1)-\frac{72(1)}{2(-2)+1} }{(2(-2)+1)^2}$
[Pre-Algebra] Multiply: $y''(-1,-2) = \frac{-48+12-\frac{72}{-4+1} }{(-4+1)^2}$
[Pre-Algebra] Add: $y''(-1,-2) = \frac{-36-\frac{72}{-3} }{(-3)^2}$
[Pre-Algebra] Exponents: $y''(-1,-2) = \frac{-36-\frac{72}{-3} }{9}$
[Pre-Algebra] Divide: $y''(-1,-2) = \frac{-36+24 }{9}$
[Pre-Algebra] Add: $y''(-1,-2) = \frac{-12}{9}$
[Pre-Algebra] Simplify: $y''(-1,-2) = \frac{-4}{3}$

6 0

2 years ago

Use the picture for the question and the answer choices:)

Orlov [11]

Parenthesis first 5-2=3.

7^2=49

-3*3=-9

49-9=40.

A is your answer.

8 0

3 years ago

Round 71.491 to the place of the underlined digit which is the 4

TiliK225 [7]

When rounding the 4 you look to the right of the number, which is the 4, and if the number is higher than 5 you would change the 4 to 5.
Therefore: 71.5

5 0

3 years ago