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2 years ago

If △CFE≅△PTR, complete each of the following statements:

Mathematics

1 answer:

Ivahew [28]2 years ago

7 0

Based on the definition of congruent triangles, the statements will be completed as follows:

CE ≅ PR
TR ≅ FE
∠P ≅ ∠C
∠F ≅ ∠T
△FEC ≅ △TRP
△RPT ≅ △ECF

Recall the following about Congruent Triangles:

The three angles of one triangle is congruent to the three corresponding angles in another triangle if both triangles are congruent triangles.

The three sides of one triangle is congruent to the three corresponding sides in another triangle if both triangles are congruent triangles.

Given that △CFE≅△PTR, thus:

CE corresponds to PR, therefore CE ≅ PR
FE corresponds to TR, therefore FE ≅ TR
CF corresponds to PT, therefore CF ≅ PT
∠P corresponds to ∠C, therefore ∠P ≅ ∠C
∠T corresponds to ∠F, therefore ∠T ≅ ∠F
∠R corresponds to ∠E, therefore ∠R ≅ ∠E

Thus, based on the definition of congruent triangles, the statements will be completed as follows:

CE ≅ PR
TR ≅ FE
∠P ≅ ∠C
∠F ≅ ∠T
△FEC ≅ △TRP
△RPT ≅ △ECF

Learn more about congruent triangles on:]

brainly.com/question/8876876

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Answer:

x= 12

Step-by-step explanation

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then divide by 3 on both sides

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which leaves : x=12

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3 years ago

Yesterday, the temperature et noon was 11.4" misright, the tempe tine had decreed by 15.7 degrees what was the

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-4.3 degrees

Step-by-step explanation:

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3 years ago

The 11 foot long bed of a dump truck loaded with debris must rise an angle of degrees before the debris will spill out. Approxim

Ymorist [56]

Answer:

The answer is below

Step-by-step explanation:

The question is not complete. The complete question is:

The 12 foot long bed of a dump truck loaded with debris must rise an angle of 30 degrees before the debris will spill out. Approximately how high must the front of the bed rise for the debris to spill out.

Solution:

Let x be the height of the front of the bed rise needed to be raised for the debris to spill out. We can find x using trigonometric identities. That is:

sin θ = opposite / hypotenuse

Using trigonometric identities, we can get that:

sin(30) = x / 12

This gives:

0.5 = x / 12

Cross multiplying the terms to get:

x = 12 * 0.5

x = 6 ft

Therefore the front of the bed rise must be raised 6 ft for the debris to spill out.

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3 years ago

Let X represent the amount of gasoline (gallons) purchased by a randomly selected customer at a gas station. Suppose that the me

Alexus [3.1K]

Answer:

a) 18.94% probability that the sample mean amount purchased is at least 12 gallons

b) 81.06% probability that the total amount of gasoline purchased is at most 600 gallons.

c) The approximate value of the 95th percentile for the total amount purchased by 50 randomly selected customers is 621.5 gallons.

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums, we can apply the theorem, with mean $\mu$ and standard deviation $s = \sqrt{n}*\sigma$

In this problem, we have that:

$\mu = 11.5, \sigma = 4$

a. In a sample of 50 randomly selected customers, what is the approximate probability that the sample mean amount purchased is at least 12 gallons?

Here we have $n = 50, s = \frac{4}{\sqrt{50}} = 0.5657$

This probability is 1 subtracted by the pvalue of Z when X = 12.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{12 - 11.5}{0.5657}$

$Z = 0.88$

$Z = 0.88$ has a pvalue of 0.8106.

1 - 0.8106 = 0.1894

18.94% probability that the sample mean amount purchased is at least 12 gallons

b. In a sample of 50 randomly selected customers, what is the approximate probability that the total amount of gasoline purchased is at most 600 gallons.

For sums, so $mu = 50*11.5 = 575, s = \sqrt{50}*4 = 28.28$