Answer:
a. 40°
b. 21°
Step-by-step explanation:
a. Reference angle = θ
Opposite = 5
Adjacent = 6
Apply TOA:
(nearest degree)
b. Reference angle = x
Opposite = 5
Hypotenuse = 14
Apply SOH:
(nearest degree)
Multiply (5x^2 + x-4(x+2)
1 answer:
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The Law of Cosines is always preferable when there's a choice. There will be two triangle angles (between 0 and 180 degrees) that share the same sine (supplementary angles) but the value of the cosine uniquely determines a triangle angle.
To find a missing side, we use the Law of Cosines when we know two sides and their included angle. We use the Law of Sines when we know another side and all the triangle angles. (We only need to know two of three to know all three, because they add to 180. There are only two degrees of freedom, to answer a different question I just did.
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The squared distance from (x,y) to the line y=k is </span>
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The squared distance from (x,y) to (p,q) is </span>
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These are equal in a parabola:
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Gotta go; more later if I can.
<span>3.There are two fruit trees located at (3,0) and (−3, 0) in the backyard plan. Maurice wants to use these two fruit trees as the focal points for an elliptical flowerbed. Johanna wants to use these two fruit trees as the focal points for some hyperbolic flowerbeds. Create the location of two vertices on the y-axis. Show your work creating the equations for both the horizontal ellipse and the horizontal hyperbola. Include the graph of both equations and the focal points on the same coordinate plane.
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The Law of Cosines is always preferable when there's a choice. There will be two triangle angles (between 0 and 180 degrees) that share the same sine (supplementary angles) but the value of the cosine uniquely determines a triangle angle.
To find a missing side, we use the Law of Cosines when we know two sides and their included angle. We use the Law of Sines when we know another side and all the triangle angles. (We only need to know two of three to know all three, because they add to 180. There are only two degrees of freedom, to answer a different question I just did.
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We'll use the standard parabola, oriented in the usual way. In that case the directrix is a line y=k and the focus is a point (p,q).
The points (x,y) on the parabola are equidistant from the line to the point. Since the distances are equal so are the squared distances.
The squared distance from (x,y) to the line y=k is </span>
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The squared distance from (x,y) to (p,q) is </span>
These are equal in a parabola:
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</span>
Gotta go; more later if I can.
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Answer:
and
Step-by-step explanation:
First make all the fractions into improper fractions
After doing that put them back into the problems
Problem 1)
÷
, plug in the improper fractions
÷
to divide, you need to flip the second fraction and multiply
·
=
then reduce
Problem 2)
÷
Plug in improper fraction
÷
Then flip second fraction and multiply
·
Multiply
Reduce, or make it a mixed number