Answer:
The correct answer is C. <em>"Cartilage, smooth muscle layers, mucosa, circular muscle". </em>
Explanation:
The intestine wall is conformed of 4 layers: mucosa, submucosa, muscular and serous.
- The mucosa layer is composed of cylindrical simple epithelium that shapes tubular glands named Lieberkühn crypts and villus, these las one in charge of absorption. The crypts are invaginations of the epithelial surface and they have the stem cells. The epithelial cells renew constantly, so cells divide in the base of the crypts and then they move to the superior portion of the digestive tube, where they die. This layer also has a basal sheet and a thin muscular sheet.
- The submucosa layer is composed of dense connective tissue, with adipose tissue located in some specific areas and large-caliber blood vessels.
- The muscular layer is composed of two bands disposed perpendicularly between them, the <u>internal thick circular muscle</u> and the <u>external thin longitudinal muscle layer</u>.
- The serouse layer is composed of a very thin connective tissue that in some points continues with the peritoneum.
Answer:
c) hypoglycemia
Explanation:
Hyperglycemia refers to the condition in which blood contains low amount of sugar or glucose molecules. The feeling of hunger, sweating and weakness of muscles are the symptoms of this disease and we know that the child has weak muscles so we can say that the child is suffering from hypoglycemia which is another disease that is present in the child.
Prokaryotic cells do not have a nucleus, animals cells have a nucleus and plant cells have a nucleus. Animal cells and plant cells are both eukaryotic.
Answer: 43 x 10^6 CFU.
Explanation:
Plate count is a method used to determine the number of viable microorganisms in a sample. When the bacterial concentration is high, serial dilutions are carried out in a 1:10 sequence. <u>Then, the dilutions are successive dilutions keeping the dilution factor constant at each step</u>. Small aliquots of these dilutions are seeded in medium contained in a Petri dish where the bacteria grow forming colonies. Then the plates are incubated and colonies develop both within the agar and on the surface.
If the concentration of the seeded aliquot is too high, the bacteria will grow too much and it will not be possible to distinguish the colonies. <u>However, if the concentration is very low, the number of colony forming units (CFU) may be very low and thus can be counted</u>.
Colony forming units are calculated:
CFU = Number of colonies / (volume seeded on the plate * dilution).
The dilution is 10^-6, the number of colonies counted is 43, and usually the volume plated is 0.1 mL, so we replace that in the equation:
CFU= 43 / (0.1 mL * 10^-6)
CFU= 43000000 = 43 x 10^6
Answer:
sandstone, limestone, and shale. These rocks often start as sediments carried in rivers and deposited in lakes and oceans. When buried, the sediments lose water and become cemented to form rock. Tuffaceous sandstones contain volcanic ash.
