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elena-s [515]
3 years ago
15

How do I complete the square for 4x^2+ 8x-5= 0?

Mathematics
2 answers:
Natalka [10]3 years ago
7 0

Answer:

man I have no idea dude I don't really know squares if you're talking about square root I really don't know

Arturiano [62]3 years ago
3 0

Answer:

x = \frac{1}{2},  -  \frac{5}{2}

Step-by-step explanation:

This is not so fun!

4x^{2}  + 8x - 5 = 0\\

Step 1:  Move the 5 to the right side

4x^{2} +8x = 5

Step 2:  Divide thru by 4

x^{2} + 2x  = \frac{5}{4}

Step 3:  Divide 2 (from 2x)  by 2 and square the result and add that to both sides of the equation.

2/2 = 1    1 squared = 1

x^{2}  + 2x + 1 = \frac{5}{4} +1 = \frac{9}{4}

Step 4:  Factor the left side

(x + 1)^{2}  = \frac{9}{4}

Step 5:   Take the square root of both sides

x + 1 = ±\sqrt{\frac{9}{4} } =  ± \frac{3}{2}

Step 6:   Move the 1 to the right side and add the results

x = -1 ± \frac{3}{2} = -1 +  \frac{3}{2}   or -1 -  \frac{3}{2}

              = \frac{1}{2}    or   -  \frac{5}{2}

And bingo, you have the solutions by completing the square.  Lot of fun, huh.  

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