Question

How do I complete the square for 4x^2+ 8x-5= 0?

Answer 1

Answer:

man I have no idea dude I don't really know squares if you're talking about square root I really don't know

Answer 2

Answer:

x = $\frac{1}{2}$,  -  $\frac{5}{2}$

Step-by-step explanation:

This is not so fun!

$4x^{2} + 8x - 5 = 0$

Step 1:  Move the 5 to the right side

$4x^{2} +8x = 5$

Step 2:  Divide thru by 4

$x^{2} + 2x = \frac{5}{4}$

Step 3:  Divide 2 (from 2x)  by 2 and square the result and add that to both sides of the equation.

2/2 = 1    1 squared = 1

$x^{2} + 2x + 1 = \frac{5}{4} +1 = \frac{9}{4}$

Step 4:  Factor the left side

$(x + 1)^{2} = \frac{9}{4}$

Step 5:   Take the square root of both sides

x + 1 = ±$\sqrt{\frac{9}{4} }$ =  ± $\frac{3}{2}$

Step 6:   Move the 1 to the right side and add the results

x = -1 ± $\frac{3}{2}$ = -1 +  $\frac{3}{2}$   or -1 -  $\frac{3}{2}$

              = $\frac{1}{2}$    or   -  $\frac{5}{2}$

And bingo, you have the solutions by completing the square.  Lot of fun, huh.