Solve the equation for y (Y-3)^2=4y-12

1 answer:

8 0

(Y-3)^2 = 4y -12 <=> Y^2 - 6Y + 9 = 4y - 12 <=> 4y = Y^2 - 6Y + 21 <=> y = (Y^2 - 6Y + 21)/4. Solving the equation for y means that we have to express y relative to the other quantities in the equation.

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Step-by-step explanation:

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✍ For x :

${ \tt{ \sin( \theta) = \frac{opposite}{hypotenuse} }} \\ \\ { \tt{ \sin(45 \degree) = \frac{x}{6} }} \\ \\ { \tt{x = 6 \times \sin(45 \degree) }} \\ { \tt{x = 4.24}}$

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${ \tt{ \cos( \theta) = \frac{adjacent}{hypotenuse} }} \\ \\ { \tt{ \cos( 45 \degree) = \frac{y}{6} }} \\ \\ { \tt{y = 6 \times \cos(45 \degree) }} \\ { \tt{y = 4.24}}$