Answer:
0.25s
Step-by-step explanation:
As v = 1.5 cos(4πt), v is maximum when cos(4πt) is maximum = 1. So the maximum velocity would be 1.5 m/s
Both the lowest and highest position occurs when its derivative is 0, aka v = 0 and has a change of direction
1.5 cos(4πt) = 0
cos(4πt) = 0
4πt = π/2 and 4πt = 3π/2
t = 1/8 = 0.125s and t = 3/8 = 0.375s
So the time it takes to travels from 1 point of time (0.125s) to another point of time (0.375) is
Answer: y = 1.73*x - 0.46
Step-by-step explanation:
For a linear equation of the form:
y = a*x + b
Where a is the slope and b is the y-intercept.
If we have an angle of A degrees with respect to the x-axis, the slope of the function can be calculated as:
Tan(A) = a.
in this case, we have we have an inclination of 30° to the positive x-axis (measured from the positive y-axis) and we know that the angle between the positive x-axis and the positive y-axis is 90°, then the angle measured from the positive axis will be such that:
A + 30° = 90
A = 90° - 30° = 60°
Then the slope is:
a = Tan(60°) = 1.73
Then we have the equation:
y = 1.73*x + b
And we know that this line passes through the point (2, 3) then we can replace x by 2 and y by 3 in the equation, and find the value of b.
3 = 1.73*2 + b
3 - 1.73*2 = b = -0.46
Then the equation is:
y = 1.73*x - 0.46
Answer:
The answer my friend is 3.1818181818181817
Step-by-step explanation:
My explanation is when you divide 35 and 11 you get 3.18 if you round it to the tenths it would be 0.01. HOPES THIS HELP HAVE A WONDERFUL REST OF YOUR DAY MARK ME BRAINLIEST PLZ.
The building would be 100ft tall. You have to take 20/6 = ?/30 The difference between 6 and 30 is x5. Then all you have to do is 20x5 and you get 100ft.
Given:
A transformation was performed on PQRS to form P'QʻR'S'.
To find:
The transformation.
Solution:
The given graph shows two similar polygons. It means, dilation was performed.
From the given graph it is clear that,
units
units
Now,
A dilation factor of 
was performed on PQRS to form P'QʻR'S'.
Therefore, the correct option is (3).
