We know that
[lateral surface area of a regular triangular pyramid]=3*[area of one <span>equilateral triangle]
so
[area of one </span>equilateral triangle]=lateral surface/3-----> 81/3-----> 27 ft²
[<span>surface area of the regular triangular pyramid]=lateral area+area of the base
area of the base is equals to the area of the lateral sides because are </span>equilateral triangles
therefore
area of the base=27 ft²
[surface area of the regular triangular pyramid]=81+27----> 108 ft²
the answer is
<span>the surface area of the regular triangular pyramid is 108 ft</span>²
Answer:
We get ∠A =40° and ∠B = 140° and ∠B = 140° is measure of larger angle
Step-by-step explanation:
we have ∠A = (2x − 30)° and ∠B = 4x, and we need to find measure of larger angle. And ∠A and ∠A are supplementary angles.
If the angles are supplementary there sum is equal to 180° i.e ∠A + ∠B = 180°
So, First we have to find the value of x. and then we can determine larger angle.
We know: ∠A + ∠B = 180
2x-30+4x=180
6x-30=180
6x=180+30
6x=210
x=210/6
x=35
So, value of x is x=35
Now finding ∠A and ∠B
∠A = (2x − 30)°
∠A = (2(35) − 30)°
∠A = (70 − 30)°
∠A =40°
and ∠B = 4x
∠B = 4(35)
∠B = 140°
So, we get ∠A =40° and ∠B = 140° and ∠B = 140° is measure of larger angle
Answer:
9
Step-by-step explanation:
Pythagorean Theorem
a²+b²=c²
(c² is the hypotenuse)
a² + 40² = 41²
a² + 1,600 = 1,681
subtract 1681-1600 in order to isolate a², which is the missing leg we are trying to find
a² = 81 in order to find our answer, we isolate a by squaring both sides
√a² = √81
a = 9
Our answer is 9.
Thee function is given as:
<span>v(t)=t^2−2tv(t)=t^2−2t
</span>(a) What is the initial velocity?
Base from the function, the initial velocity would be zero.
(b) When does the object have a velocity of zero?
It would be during time zero. Also, at a time equal to two.
