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xeze [42]
2 years ago
6

Annie, Brianna & Carly are selling fruit boxes to raise money for their soccer team. All together the girls have sold 105 bo

xes of fruit. Carly has sold ten more than three times Brianna's sales. Brianna sold five more than Annie. How many boxes of fruit did Carly sell?
Mathematics
1 answer:
GaryK [48]2 years ago
6 0

Step-by-step explanation:

Annie = x

Brianna = y

Carly = z

Now,

x + y + z = 105 ...(1)

Carly has sold ten more than three times Brianna's sales.

z = 10 + 3y ...(2)

Brianna sold five more than Annie.

y = 5 + x ...(3)

Now,

z = 10 + 3y

z = 10 + 3(5 + x)

z = 10 + 15 + 3x

z = 25 + 3x

Now,

x + y + z = 105

x + (5 + x) + 25 + 3x = 105

5x + 30 = 105

5x = 105 - 30

5x = 75

5x/5 = 75/5

x = 15

So,

y = 5 + x

y = 5 + 15

y = 20

Now,

z = 25 + 3x

z = 25 + 3(15)

z = 25 + 45

z = 70

Thus,

Annie Sold 15 boxes

Brianna Sold 20 boxes

Carly Sold 70 boxes

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There are three clubs at Redwood High School: Debate, Student council, and Key club. There are 1000 students in the school. And
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Answer:

The number of students in the key club is 490

Step-by-step explanation:

The given parameters are;

The number of student in the school = 1000

The total number of student in the debate club = 310

The total number of student in the student council = 650

The total number of student who are in debate and student council = 170

The total number of student who are in both debate and the key club = 150

The total number of student who are in both student council and the key club = 180

The number of students who are in all three clubs = 50

Therefore, we have;

Let A represent the number of students in the debate club

Let B represent the number of students in the student council

Let C represent the number of students in the key club

We have;

n(A∪B∪C) = n(A) + n(B) + n(C) -  n(A∩B) - n(B∩C) - n(C∩A) + n(A∩B∩C)

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n(A∪B∪C) = 1000

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n(B∩C) = 180

n(C∩A) = 150

n(A∩B∩C) = 50

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n(C) = n(A∪B∪C) - (n(A) + n(B) -  n(A∩B) - n(B∩C) - n(C∩A) + n(A∩B∩C))

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