3 and a half cookies! that should be the answer!
Thxxxxxxxxxxxxxxxxxxcxxxxxxxxxxxcxxxxx
50% =
0.5 =
50/100 =
1/2
This cannot be written as an improper fraction
Answer:
We accept H₀
Step-by-step explanation:
Normal Distribution
size sample n = 69
sample mean 18.94
standard deviation 8.3
Is a one tailed-test to the left we are traying of find out is we have enough evidence to say that the mean is less than 20 min.
1.-Test hypothesis H₀ ⇒ μ₀ = 20
Alternative hypothesis Hₐ ⇒ μ₀ < 20
2.- Critical value
for α = 0.1 we find from z Table
z(c) = - 1.28
3.-We compute z(s)
z(s) = [ ( μ - μ₀ ) / (σ/√n) ⇒ z(s) = [( 18.94 - 20 )*√69)/8.3]
z(s) = ( -1.06)*8.31/8.3
z(s) = - 1.061
4.- We compare
z(c) and z(s) -1.28 > -1.061
Then z(c) > z(s)
z(s) in inside acceptance region so we accept H₀
7:14 or simplified 1:2 (use simplified)
Find total amount of fruit by adding
4+7+3=14
7 pears to 14 total fruits in ratio form is 7:14 which simplifies to 1:2
