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Elan Coil [88]
3 years ago
8

SOMEONE HELP ME PLEASE! I’m trying to do my homework and this is hard! It’s linear functions. Also it’s number 3

Mathematics
2 answers:
Setler79 [48]3 years ago
8 0

Answer:

y = x + 4

slope = 1

y-intercept = 4

Step-by-step explanation:

Take two coordinates, (0, 4) and (1, 5) for example. It's rise over run so y is on top of x. So you would subtract the y's, 5 - 4, and subtract the x's, 1 - 0. That would be 1 over 1, which would just be 1. Then plug in the x and y coordinates; any pair of coordinates will be fine. The equation should look like this, 4 = 1(0) + b. 1 times 0 is 0 so that makes b, the y-intercept, 4, giving you, y = x + 4 as your equation.

kondaur [170]3 years ago
5 0

Answer:

A. y = 1x + 4

B. 1

C. 4

Step-by-step explanation:

The point (0, 4) is the y-intercept. So b = 4

y goes up each time by 1. So m = 1

Plug into y = mx + b

y = 1x + 4

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Read 2 more answers
PLEASE HELP ME PLEASE HELP ASAP PLEASE HELP PLEASE AND THANK YOU
Allushta [10]

Answer:

y =mx + c

7 = 5/2 (-2) + c

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Therefore, y = 5/2x + 12

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You're welcome

7 0
3 years ago
The matrix C=[1,-2_-3,7] was used to encode a phrase to [7,-28,-25,-35,-2_-21,107,90,123,17]. Find C^-1 and use it to decode the
posledela
C=  \left[\begin{array}{cc}1&-2\\-3&7\end{array}\right]  \\ C^{-1}= \left[\begin{array}{cc}7&2\\3&1\end{array}\right]  \\ \left[\begin{array}{cc}7&2\\3&1\end{array}\right] \times   \left[\begin{array}{ccccc}7&-28&-25&-35&-2\\-21&107&90&123&17\end{array}\right]  \\ =\left[\begin{array}{ccccc}49-42&-196+214&-175+180&-245+246&-14+34\\21-21&-84+107&-75+90&-105+123&-6+17\end{array}\right] \\ =\left[\begin{array}{ccccc}7&18&5&1&20\\0&23&15&18&11\end{array}\right]
is the required matrix.
6 0
3 years ago
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