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3 years ago

SOMEONE HELP ME PLEASE! I’m trying to do my homework and this is hard! It’s linear functions. Also it’s number 3

Mathematics

2 answers:

Setler79 [48]3 years ago

8 0

Answer:

y = x + 4

slope = 1

y-intercept = 4

Step-by-step explanation:

Take two coordinates, (0, 4) and (1, 5) for example. It's rise over run so y is on top of x. So you would subtract the y's, 5 - 4, and subtract the x's, 1 - 0. That would be 1 over 1, which would just be 1. Then plug in the x and y coordinates; any pair of coordinates will be fine. The equation should look like this, 4 = 1(0) + b. 1 times 0 is 0 so that makes b, the y-intercept, 4, giving you, y = x + 4 as your equation.

kondaur [170]3 years ago

5 0

Answer:

A. y = 1x + 4

B. 1

C. 4

Step-by-step explanation:

The point (0, 4) is the y-intercept. So b = 4

y goes up each time by 1. So m = 1

Plug into y = mx + b

y = 1x + 4

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2 years ago

How do you find a vector that is orthogonal to 5i + 12j ?

Rashid [163]

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-------------------------------\\\\$

$\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
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if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

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\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}
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3 years ago

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