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3 years ago

SOMEONE HELP ME PLEASE! I’m trying to do my homework and this is hard! It’s linear functions. Also it’s number 3

Mathematics

2 answers:

Setler79 [48]3 years ago

8 0

Answer:

y = x + 4

slope = 1

y-intercept = 4

Step-by-step explanation:

Take two coordinates, (0, 4) and (1, 5) for example. It's rise over run so y is on top of x. So you would subtract the y's, 5 - 4, and subtract the x's, 1 - 0. That would be 1 over 1, which would just be 1. Then plug in the x and y coordinates; any pair of coordinates will be fine. The equation should look like this, 4 = 1(0) + b. 1 times 0 is 0 so that makes b, the y-intercept, 4, giving you, y = x + 4 as your equation.

kondaur [170]3 years ago

5 0

Answer:

A. y = 1x + 4

B. 1

C. 4

Step-by-step explanation:

The point (0, 4) is the y-intercept. So b = 4

y goes up each time by 1. So m = 1

Plug into y = mx + b

y = 1x + 4

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In prima zi de la lansarea noii cartii a scriitorului preferat al Elizei s-au vandut 24 de volume adica 6 _ 7

TiliK225 [7]

Answer:

Step-by-step explanation:

3 0

3 years ago

Will give brainliest plzzzzz.Which statement justifies why ∠EBC measures 90°? Given: angles ABD and DBC are complementary Point

Anettt [7]

Answer:

he sum of the measures of two complementary angles is 90 degrees

Step-by-step explanation:

we know that

If two angles are complementary, then their sum is equal to 90 degrees

In this problem we have that

m∠ABD and m∠DBC are complementary

m∠ABD + m∠DBC=90° -----> by complementary angles

and

(m∠ABD + m∠DBC)+m∠EBC=180° -----> by a linear pair

Find the measure of angle EBC

substitute the given values

(90°)+m∠EBC=180°

∠EBC=180°-90°=90°

5 0

3 years ago

The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont

BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

$\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)$

and its cumulative distribution function (CDF) is

$\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}$

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

$\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347$

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so A∩B = B and

$\bf P(A | B) = P(B)P(B) = (P(B))^2$

We have

$\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237$

hence,

$\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313$

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

$\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}$

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection = </em>

$\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021$