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shtirl [24]
2 years ago
15

If anyone knows how to do this please help, its for a test and I have to finish the course by 11:59 tonight

Mathematics
2 answers:
GalinKa [24]2 years ago
4 0
It’s c


i have to type more than 20 characters so don’t mind this
abruzzese [7]2 years ago
3 0
The correct answer would be c. hope this helps
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Which weighs more 5 ounces or 150 grams
Karo-lina-s [1.5K]
150 grams weigh more than 5 ounces
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The area of a rectangle is 65 m2 , and the length of the rectangle is 3 m less than twice the width. find the dimensions of the
salantis [7]
X = <span>width
2x-3 = </span><span>length 

</span>x(2x-3) = 65\\&#10;2x^2 - 3x - 65 = 0 \\ D=b^2-4ac=(-3)^2-4*2*(-65)=529\\&#10;x_{1,2}= \frac{-bб \sqrt{D} }{2a}= \frac{3б 23}{4} \\ x_1=-5  \ \ \O \\ x_2=6.5 \ \

width = 6.5 m
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4 0
3 years ago
What is the solution to the equation 1/4x = 5?
puteri [66]
The solution to your equation is:

Solve:
1/4x = 5

Step 1: Multiply both sides by 4
4 * (1/4x) = (4) * (5)

x = 20


Thus your answer is:

Letter Choice (C), x = 20





Hope that helps!!!



5 0
2 years ago
Find the polynomial of least degree to be added to 6x^2+8x^3+17x^2+12x+7 so that 3x^2+4x+1 is a factor. Class ten questions
AURORKA [14]
Hope that really helps you

3 0
2 years ago
A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0
3 years ago
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