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shtirl [24]
3 years ago
15

If anyone knows how to do this please help, its for a test and I have to finish the course by 11:59 tonight

Mathematics
2 answers:
GalinKa [24]3 years ago
4 0
It’s c


i have to type more than 20 characters so don’t mind this
abruzzese [7]3 years ago
3 0
The correct answer would be c. hope this helps
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Kinda stuck please help would appreciate it :)
V125BC [204]

<em>Answer,</em>

<em>2w - 5 = 8</em>


<u><em>Hope this helps :-)</em></u>

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3 years ago
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How many thirds are there in 1 whole.write in numerator and a denominator
Salsk061 [2.6K]
3 would be the answer to that!
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3 years ago
Question 2 of 10
artcher [175]

Answer:

D

Step-by-step explanation:

8 0
2 years ago
If the radius of mars is about 13.7% of neptune's radius, what is the radius of neptune?
Marianna [84]
The volumetric mean radius of Mars is about 3389.5 km. We know that it's 13.7% of Neptune's mean radius, so we can write it down as:

3389.5 = 13.7% of x (where x is Neptune's radius)
3389.5 = 13.7% x
3389.5 = 137/1000x                / * 1000 (both sides)
3389500 = 137x                       / ÷ 137 (both sides)
x = 24740.87591240876
x ≈ 24740.88

Answer: The mean radius of Neptune is about 24740.88 km.
6 0
3 years ago
Divide 29 into two parts so that the sun of the squares of the parts is 425.Find the value of each Part.
Taya2010 [7]

Answer:

13 and 16

Step-by-step explanation:

let the 2 parts be x and y, then

x + y = 29 → (1) and

x² + y² = 425 → (2)

From (1) → x = 29 - y → (3)

substitute x = 29 - y into (2)

(29 - y)² + y² = 425 ( expand factor )

841 - 58y + y² + y² = 425 ( rearrange into standard form )

2y² - 58y + 416 = 0 ← in standard quadratic form

divide all terms by 2

y² - 29y + 208 = 0

Consider the factors of 208 which sum to - 29

These are - 13 and - 16, hence

(y - 13)(y - 16) = 0

equate each factor to zero and solve for y

y - 13 = 0 ⇒ y = 13

y - 16 = 0 ⇒ y = 16

substitute these values into (3)

x = 29 - 13 = 16 and x = 29 - 16 = 13

The 2 parts are 13 and 16


4 0
3 years ago
Read 2 more answers
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