All categories

2 years ago

1. Alan got 80% in his math test, Jorden got one-fifth more, what is the mark of Jorden?

Mathematics

2 answers:

nignag [31]2 years ago

6 0

Answer:

1. 96%

2. $6000

3. 176

4. 20%

Step-by-step explanation:

1. 1/5 of 80% is 16%. 80+16=96

2. 25% of 8000 is 2000. 8000-2000= 6000.

3. 10% increase of 200 is 20. 20+200=220. 20 percent of 220 is 44. 220-44=176

4. if you increase the original salary by 20%, then decreasing it by 20% of the new salary will give you the old salary.

castortr0y [4]2 years ago

4 0

Answer:

63,000

Step-by-step explanation:

You might be interested in

A train is traveling at a constant speed. The diagram represents the train's distance and time. What is the speed of the train?

Over [174]

240÷6=40 so the answer would be "The train is traveling 40 miles per hour."

6 0

3 years ago

Read 2 more answers

Rajiv and his family left home on a trip and drove for 2 hours before they stopped to eat. After 1.5 hours, they were back on th

Aliun [14]

Answer:

The first one is 1 and the second one is 1:00

Step-by-step explanation:

e set of words that refers to the clock is: midnight (exactly 12:00 am), morning (from 12:01 am to 11:59 am), noon (exactly 12:00 pm), afternoon (from 12:01 pm to 6:00 pm), evening (from 6:00 pm to 11:59 pm).

5 0

3 years ago

Read 2 more answers

A researcher wants to estimate the percentage of all adults that have used the Internet to seek pre-purchase information in the

Lubov Fominskaja [6]

Answer:

The required sample size for the new study is 801.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

25% of all adults had used the Internet for such a purpose

This means that $\pi = 0.25$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

What is the required sample size for the new study?

This is n for which M = 0.03. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.25*0.75)}{n}}$

$0.03\sqrt{n} = 1.96\sqrt{0.25*0.75}$

$\sqrt{n} = \frac{1.96\sqrt{0.25*0.75}}{0.03}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.25*0.75}}{0.03})^2$

$n = 800.3$

Rounding up:

The required sample size for the new study is 801.

4 0

3 years ago

Help please simplify: 4(3b)

Aleonysh [2.5K]

Answer: 12b

Step-by-step explanation: you multiply 4 by 3 but keep the b

8 0

3 years ago

Read 2 more answers

Solve for X <br> 7x=49 (brainliest)

posledela

Answer:

$\huge\colorbox{violet}{ᴀɴsᴡᴇʀ}$

Hey There!

The answer = 7 = ( Seventh Track of TS8= Seven )

Step-by-step explanation:

$7x = 49 \\ x = 49 \div 7 \\ x = 7$

$7 \times 1 = 7 \\ 7 \times 2 = 14\\ 7 \times 3 = 21 \\ 7 \times 4 = 28 \\ 7 \times 5 = 35 \\ 7 \times 6 = 42 \\ \bold {7 \times 7 = 49} \\ 7 \times 8 = 56 \\ 7 \times 9 = 63 \\ 7 \times 10 = 7$

6 0

3 years ago

Read 2 more answers