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2 years ago

The length of the observable universe is.

Mathematics

1 answer:

alekssr [168]2 years ago

5 0

Answer:

Kindly check explanation

Step-by-step explanation:

Organizations like NASA who explore space and planets often have to deal with measurement of very long distances such as the one stated above. The Major challenge with the distance written in the format expressed above is the difficulty to read, state or use in mathematical calculations as it is too explicit. A more effective method is to express this distance in standard format and more suitable long distant units such as miles.

For instance;

880,000,000,000,000,000,000,000 kilometers could be expressed as in standard form as ;

8.8 * 10^23 km

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a student showed the steps below while solving the equation 14=log5(2x-3) by graphing. which step did the student make the 1sr e

mixer [17]

Answer:

$x= \frac{5^{14}+3}{2}$

Step-by-step explanation:

The correct steps to solve the equation are:

$14=log_5(2x-5)$

$5^{14}=5^{log_5(2x-3)}$

Because $a^{log_am}=m$

So, solving we get:

$5^{14}=2x-3$

Sum 3 on every side:

$5^{14}+3=2x-3+3\\5^{14}+3=2x$

Dividing by 2 into both sides:

$\frac{5^{14}+3}{2}=\frac{2x}{2}\\\frac{5^{14}+3}{2}=x$

So, the answer is $x= \frac{5^{14}+3}{2}$

7 0

3 years ago

Rebecca and dan are biking in a national park for three days they rode 5 3/4 hours the first day and 6 4/5 hours the second day

AfilCa [17]

Answer:

Rebecca and Dan need to ride $7\frac{9}{20}\ hrs.$ on the third day in order to achieve goal of biking.

Step-by-step explanation:

Given:

Goal of Total number of hours of biking in park =20 hours.

Number of hours rode on first day = $5\frac34 \ hrs.$

So we will convert mixed fraction into Improper fraction.

Now we can say that;

To Convert mixed fraction into Improper fraction multiply the whole number part by the fraction's denominator and then add that to the numerator,then write the result on top of the denominator.

$5\frac34 \ hrs.$ can be Rewritten as $\frac{23}{4}\ hrs$

Number of hours rode on first day = $\frac{23}{4}\ hrs$

Also Given:

Number of hours rode on second day = $6\frac45 \ hrs$

$6\frac45 \ hrs$ can be Rewritten as $\frac{34}{5}\ hrs.$

Number of hours rode on second day = $\frac{34}{5}\ hrs.$

We need to find Number of hours she need to ride on third day in order to achieve the goal.

Solution:

Now we can say that;

Number of hours she need to ride on third day can be calculated by subtracting Number of hours rode on first day and Number of hours rode on second day from the Goal of Total number of hours of biking in park.

framing in equation form we get;

Number of hours she need to ride on third day = $20-\frac{23}{4}-\frac{34}{5}$

Now we will use LCM to make the denominators common we get;

Number of hours she need to ride on third day = $\frac{20\times20}{20}-\frac{23\times5}{4\times5}-\frac{34\times4}{5\times4}= \frac{400}{20}-\frac{115}{20}-\frac{136}{20}$

Now denominators are common so we will solve the numerator we get;

Number of hours she need to ride on third day = $\frac{400-115-136}{20}=\frac{149}{20}\ hrs \ \ Or \ \ 7\frac{9}{20}\ hrs.$

Hence Rebecca and Dan need to ride $7\frac{9}{20}\ hrs.$ on the third day in order to achieve goal of biking.

3 0

3 years ago

Land once connecting asia and north america

Whitepunk [10]

The land bridge, It includes the Chukchi Sea, the Bering Sea, the Bering Strait, the Chukchi and Kamchatka Peninsulas in Russia as well as Alaska in the United States. The area includes land lying on the North American Plate and Siberian land east of the Chersky Range.

You could've just looked it up dude.

7 0

3 years ago

Machine M, working alone at its constant rate, produces x widgets every 4 minutes. Machine N, working alone at its constant rate

Harman [31]

Answer:

Yes

Step-by-step explanation:

Given that Machine M, working alone at its constant rate, produces x widgets every 4 minutes. Machine N, working alone at its constant rate, produces y widgets every 5 minutes.

When both machines work for 20 minutes

Machine A would produce = $\frac{20}{4} =5$ widget and

Machine B would produce = $\frac{20}{5} =4$ widgets

So we can say that Machine A would produce more widgets than Machine N at that time.

Answer is Yes

8 0

3 years ago

The value of 4 in 64513 is how many times the value of 4 in

il63 [147K]

It will be

(4,000) divided by (the value of 4 in the number you left out).

7 0

2 years ago