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2 years ago

Can someone help me with my mid term click download document

Mathematics

1 answer:

kari74 [83]2 years ago

7 0

Answer:

1.D 2.D 3.B 4.B 5.B 6.B 7.C 8.C 9. Tickets sold/money collected

10. Tickets sold 11. Money collected 12. The money collected is 2 times more than tickets sold. 13. 80 dollars 14. 6 hours 15. Go by 25 on the y-axis (25 on first line, 50 on second line, 75 on 3rd line) and match them up to your table.

P.S. I'm not sure about my responses. Go check to make sure I'm right on them.

Step-by-step explanation:

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Write an equation in point-slope form for: (-3, 6) and m = 2

viktelen [127]

Y-6=2(x+3) is the answer i’m positive

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3 years ago

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Which statement about the ordered pairs (3, −8)(3, −8) and (4, 4)(4, 4) is true for the equation 3x−y4=11

sleet_krkn [62]

The answer is D.) Neither ordered pair is a solution.

The reason being:

If we look at the ordered pair (3,-8) and plug it into the equation like so:

3(3)-(-8)4=11
9-32=11
-23=11
FALSE

Now let's look at the ordered pair (4,4):

3(4)-4(4)=11
12-16=11
-4=11
FALSE

We see that neither ordered pair works, so the answer is D.) neither is a solution.

Hope this helped :)

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4 years ago

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Keats Library purchases a number of new books, all in the category of biography; the library does not acquire any other books. W

PtichkaEL [24]

Answer:

$\large \boxed{87.5 \, \%}$

Step-by-step explanation:

Let x = the original number of books

Then 0.375x = the total number of biographies

and 0.20 x = the original number of biographies

$\text{Percent increase} = \dfrac{\text{ New number - Old number }}{\text{Old number }} \times 100\, \%\\\\= \dfrac{0.375x - 0.20x}{0.20x} \times 100\, \% = \dfrac{0.175x}{0.20x} \times 100\, \% = 0.875 \times 100\, \% = \mathbf{87.5 \, \%}\\\\\text{The number of biographies has increased by $\large \boxed{\mathbf{87.5 \, \%}}$}$

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3 years ago

A^2/5 x a^-3 in the form a^n

leonid [27]

Answer:

a^(-2 3/5)

Step-by-step explanation:

When you multiply two numbers together with the same base, you can add the two exponents together. In this case, $a^{\frac{2}{5}}\cdot a^{-3}=a^{-2\frac{3}{5}}$ . Hope this helps!

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3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csf%20Evaluate%5Cint%20log%20%5C%3A%20x%20%5C%3A%20dx" id="TexFormula1" title=" \sf Evalu

Greeley [361]

Answer:

x(log(x) - 1) + C

Step-by-step explanation:

The formula for the derivative of a logarithm function is:

$\frac{d}{dx} log_{a}(x) = \frac{1}{xlog(a)}$

For your case, the base is 10. Now that we have the derivative, lets use integration by parts. I will be differentiating log(x) and integrating 1:

u = log(x)

du = dx/xlog(10)

dv = 1

v = x

You get:

log(x)x - integral(dx/log(10))

Therefore the answer is:

log(x)x - x/log(10) + C

x(log(x) - 1) + C

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2 years ago

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