Answer:
time = distance/speed
3080/770 = 4
So it took 4 hours.
Step-by-step explanation:
It is a that is your answer
Answer:
you would have to pay $43.20
Step-by-step explanation:
15+32.50=47.50
47.50x.08=3.80
47-3.80=43.20
Answer:
A could represent the volume of a full bottle of the hot sauce.
Step-by-step explanation:
If we say that a full bottle of hot sauce is 100 ml, 90% of that would be 90ml, meaning that <em>x</em> is 90ml.
In this scenario, (10/9)x would equal 100ml, so it has to be the answer.
Answer:
The volume of the ball with the drilled hole is:
![\displaystyle\frac{8000\pi\sqrt{2}}{3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7B8000%5Cpi%5Csqrt%7B2%7D%7D%7B3%7D)
Step-by-step explanation:
See attached a sketch of the region that is revolved about the y-axis to produce the upper half of the ball. Notice the function y is the equation of a circle centered at the origin with radius 15:
![x^2+y^2=15^2\to y=\sqrt{225-x^2}](https://tex.z-dn.net/?f=x%5E2%2By%5E2%3D15%5E2%5Cto%20y%3D%5Csqrt%7B225-x%5E2%7D)
Then we set the integral for the volume by using shell method:
![\displaystyle\int_5^{15}2\pi x\sqrt{225-x^2}dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint_5%5E%7B15%7D2%5Cpi%20x%5Csqrt%7B225-x%5E2%7Ddx)
That can be solved by substitution:
![u=225-x^2\to du=-2xdx](https://tex.z-dn.net/?f=u%3D225-x%5E2%5Cto%20du%3D-2xdx)
The limits of integration also change:
For x=5: ![u=225-5^2=200](https://tex.z-dn.net/?f=u%3D225-5%5E2%3D200)
For x=15: ![u=225-15^2=0](https://tex.z-dn.net/?f=u%3D225-15%5E2%3D0)
So the integral becomes:
![\displaystyle -\int_{200}^{0}\pi \sqrt{u}du](https://tex.z-dn.net/?f=%5Cdisplaystyle%20-%5Cint_%7B200%7D%5E%7B0%7D%5Cpi%20%5Csqrt%7Bu%7Ddu)
If we flip the limits we also get rid of the minus in front, and writing the root as an exponent we get:
![\displaystyle \int_{0}^{200}\pi u^{1/2}du](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint_%7B0%7D%5E%7B200%7D%5Cpi%20u%5E%7B1%2F2%7Ddu)
Then applying the basic rule we get:
![\displaystyle\frac{2\pi}{3}u^{3/2}\Bigg|_0^{200}=\frac{2\pi(200\sqrt{200})}{3}=\frac{400\pi(10)\sqrt{2}}{3}=\frac{4000\pi\sqrt{2}}{3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7B2%5Cpi%7D%7B3%7Du%5E%7B3%2F2%7D%5CBigg%7C_0%5E%7B200%7D%3D%5Cfrac%7B2%5Cpi%28200%5Csqrt%7B200%7D%29%7D%7B3%7D%3D%5Cfrac%7B400%5Cpi%2810%29%5Csqrt%7B2%7D%7D%7B3%7D%3D%5Cfrac%7B4000%5Cpi%5Csqrt%7B2%7D%7D%7B3%7D)
Since that is just half of the solid, we multiply by 2 to get the complete volume:
![\displaystyle\frac{2\cdot4000\pi\sqrt{2}}{3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7B2%5Ccdot4000%5Cpi%5Csqrt%7B2%7D%7D%7B3%7D)
![=\displaystyle\frac{8000\pi\sqrt{2}}{3}](https://tex.z-dn.net/?f=%3D%5Cdisplaystyle%5Cfrac%7B8000%5Cpi%5Csqrt%7B2%7D%7D%7B3%7D)