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2 years ago

For each item, would a milliliter or a liter be the more reasonable unit of measure?

Mathematics

2 answers:

PilotLPTM [1.2K]2 years ago

5 0

Answer:

A) liter
B) milliliter
C) milliliter

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Explanation:

An aquarium would vary in size depending on how big you want it, but usually the small sized aquariums are about 2.5 gallons in capacity, which converts to roughly 9.46 liters. If you were to convert this to milliliters (mL), then you multiply by 1000 to get 9460 mL. I think it's better to go with liters since the number is smaller and can be rounded to something like 9 liters.

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Soup cans vary in size/volume. One typical volume is 355 mL. Divide by 1000 to convert to liters. So 355 mL = 0.355 L. I think it's better to go with mL here because we have a whole number rather than a decimal. Also, the decimal value 0.355 isn't larger than 1, meaning we don't have a full liter.

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An eye dropper deals with a very small amount of liquid, so it's natural to go with the smaller unit mL instead of liters.

NARA [144]2 years ago

3 0

Answer:

Aquarium - Liter.

Soup can - milliliter.

Eye dropper - milliliter.

Hope this helps you! :)

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Answer:

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Step-by-step explanation:

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3 years ago

Solve the inequality |* +31 < |2x + 1.<br> |x+3|<|2x+1|

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Answer:

Step-by-step explanation:

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Isolate the absolute value expression on the left side of the inequality.

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3 years ago

The average amount of time that students use computers at a university computer center is 36 minutes with a standard deviation o

frosja888 [35]

Answer:

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 36, \sigma = 5$

The first step to solve this question is finding the proportion of students which use the computer more than 40 minutes, which is 1 subtracted by the pvalue of Z when X = 40. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{40 - 36}{5}$

$Z = 0.8$

$Z = 0.8$ has a pvalue of 0.7881.

1 - 0.7881 = 0.2119

So 21.19% of the students use the computer for longer than 40 minutes.

Out of 10000

0.2119*10000 = 2119

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

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3 years ago

What is the approximate area of a circle with a radius of 13cm? A.40.8cm² B.530.7cm² C.784cm² D.2461.8cm²

Gnesinka [82]

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3 years ago

Read 2 more answers

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PtichkaEL [24]

The answer you want would be -120

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