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3 years ago

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A population of cheetahs has decreased 30% over the last 18 years if they're originally about 12,000 cheetahs how many cheetahs

are there now?

1 answer:

lukranit [14]3 years ago

8 0

15600
It should be the correct answer

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ethan took a quiz with 15 questions. if he answered 3/5 of the questions correctly, how many did he get wrong?

valentina_108 [34]

$\frac{15}{1} * \frac{3}{5} = \frac{45}{5} = 9 
 



$

15-9= 6
Ethan got six questions wrong.

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You roll a die, spin the spinner, and find the sum. How many different sums are possible?

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This hurts my brain bro

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What is the median of 1, 3, 6, 8, 9, 9<br> Answer choices: A. 6<br> B. 7<br> C. 8<br> D. 9

luda_lava [24]

Answer:

B

Step-by-step explanation:

The median is the middle value of the data arranged in ascending order. If there is no exact middle value then it is the average of the values either side of the middle.

1, 3, 6, 8, 9, 9

↑ middle

median = $\frac{6+8}{2}$ = $\frac{14}{2}$ = 7 → B

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3 years ago

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What is 279 ÷34 estimated

Anestetic [448]

279/34 = 8.20588235294

But if you would like to round it up it would be 8.2 or 8.21 depending on what you'd like to round it up to.

Let me know if this is what you mean. If not, I will fix it! :)

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I need help.. i really want to go sleep.. thank you so much...

Effectus [21]

Answer:

1) True 2) False

Step-by-step explanation:

1) Given $\sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i}$

To verify that the above equality is true or false:

Now find $\sum\limits_{k=0}^8\frac{1}{k+3}$

Expanding the summation we get

$\sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{0+3}+\frac{1}{1+3}+\frac{1}{2+3}+\frac{1}{3+3}+\frac{1}{4+3}+\frac{1}{5+3}+\frac{1}{6+3}+\frac{1}{7+3}+\frac{1}{8+3}$ $\sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}$

Now find $\sum\limits_{i=3}^{11}\frac{1}{i}$

Expanding the summation we get

$\sum\limits_{i=3}^{11}\frac{1}{i}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}$

Comparing the two series we get,

$\sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i}$ so the given equality is true.

2) Given $\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\sum\limits_{i=1}^3\frac{3i}{i+5}$

Verify the above equality is true or false

Now find $\sum\limits_{k=0}^4\frac{3k+3}{k+6}$

Expanding the summation we get

$\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3(0)+3}{0+6}+\frac{3(1)+3}{1+6}+\frac{3(2)+3}{2+6}+\frac{3(3)+4}{3+6}+\frac{3(4)+3}{4+6}$

$\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}+\frac{12}{8}+\frac{15}{10}$

now find $\sum\limits_{i=1}^3\frac{3i}{i+5}$

Expanding the summation we get

$\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3(0)}{0+5}+\frac{3(1)}{1+5}+\frac{3(2)}{2+5}+\frac{3(3)}{3+5}$

$\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}$

Comparing the series we get that the given equality is false.

ie, $\sum\limits_{k=0}^4\frac{3k+3}{k+6}\neq\sum\limits_{i=1}^3\frac{3i}{i+5}$

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3 years ago