P = 3
n = 5
N = 15
<span><span><span>x </span><span>¯ </span></span> </span>
= 16
<span><span>SST</span> </span>
= <span><span>∑n(x−<span><span>x </span><span>¯ </span></span><span><span>) </span><span>2 </span></span></span> </span>
<span><span>SST</span> </span>
= <span><span>5(12−16<span><span>) </span><span>2 </span></span>+5(16−16<span><span>) </span><span>2 </span></span>+11(20−16<span><span>) </span><span>2 </span></span></span> </span>
= 160
<span><span>MST</span> </span>
= <span><span><span><span>SST</span><span>p−1</span> </span> </span>
</span>
<span><span>MST</span> </span>
= <span><span><span>160<span>3−1</span> </span> </span>
</span>
= 80
<span><span>SSE</span> </span>
= <span><span>∑(n−1)<span><span>S </span><span>2 </span></span></span> </span>
SSE = 4*4 + 4*1 + 4*16
= 84
<span><span>MSE</span> </span>
= <span><span><span><span>SSE</span><span>N−p</span> </span> </span>
</span>
<span><span>MSE</span> </span>
= <span><span><span>84<span>15−3</span> </span> </span>
</span>
MSE = 7
<span>F </span>
= <span><span><span><span>MST</span><span>MSE</span> </span> </span>
</span>
<span>F </span>
= <span><span><span>807 </span> </span>
</span>
= 11.429
Like I need to answer the whole entire page?
<span>to answer the question above, take the LHS.
[(tan x - 1) / (tan x + 1)] =
Remember that tan x = 1 / cot x.
{[(1 / cot x) - 1] / [(1 / cot x) + 1]} =
The LCD is cot x. Multiply as needed to get the common denominator for all terms.
{[(1 / cot x) - 1(cot x / cot x)] / [(1 / cot x) + 1(cot x / cot x)]} =
{[(1 / cot x) - (cot x / cot x)] / [(1 / cot x) + (cot x / cot x)]} =
Then Simplify.
[(1 - cot x) / cot x] / [(1 + cot x) / cot x] =
Remember that (a / b) / (c / d) = (a / b) * (d / c).
[(1 - cot x) / cot x] * [cot x / (1 + cot x)] =
[(1 - cot x) / (1 + cot x )] =
RHS</span>
The answer is
<span>[(tan x - 1) / (tan x + 1)] = [(1 - cot x) / (1 + cot x )] </span>
The answer for this is (-3b4) (3b4 +) = 121a10-9b8
