Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
First convert 5 1/3 into a fraction which is 16/3.
16/3 divided by 7/8 is the same as 16/3 multiplied by 8/7. So you multiply the fractions together to get 128/21.
4.0081 x 10 to the 4th power. I know because I did this one.
Answer: C. -12 - 3 + 9
Step-by-step explanation:
-12 because the fish are 12 m <em>below</em> the ocean.
-3 because the fish swim <em>down</em>.
+9 because the fish swim <em>up</em>.
