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ch4aika [34]
2 years ago
5

A series circuit contains a resistor and an inductor as shown in the figure. Determine a differential equation for the current i

(t) if the resistance is R, the inductance is L, and the impressed voltage is E(t). (Use i for i(t) and E for E(t)).
Mathematics
1 answer:
alukav5142 [94]2 years ago
8 0

From the information given, the differential equation will be di/dt = (E - Ri) / L.

<h3>How to calculate the differential equation</h3>

From the information given, we can set up the differential equation as:

-E(t) = Ldi(t)/Dr + Ti(t) = 0.

Here, i(t) = I

E(t) = E

Therefore, this will be:

= -E + Ldi/dt + Ri = 0

We'll now solve for di/dt

Ldi/dt = E - Ri

di/dt = (E - Ri) / L

Learn more about differential equations on:

brainly.com/question/1164377

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L = Length
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So
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Step-by-step explanation:

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3 years ago
Graph this function:<br> y = 2x
77julia77 [94]

Graph is attached below.

Step-by-step explanation:

We have to graph function y = 2x,

From  equation, we can see a linear relationship between the values of x and y.  This equation shows that the value of y is double than the value of x.

For example,

<u>x = 0</u>

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y = 0

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y = 2

So, point would be (1,2)

<u>x = 3</u>

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y = 6

So, point would be (3,6)

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y = -2

So, point would be (-1,-2)

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y = -6

So, point would be (-3,-6)

By matching these points, a linear graph can easily be drawn. I have also attached the graph pic below.

Keywords: function, graph

Learn more at:

brainly.com/question/1600331

brainly.com/question/2334270

#LearnwithBrainly

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−3⋅f(−8)+7⋅g(2)= <br><br> I need help!
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