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Archy [21]
3 years ago
6

A small ball of mass 0.75 kg is attached to one end of a 1.25-m-long massless rod, and the other end of the rod is hung from a p

ivot. When the resulting pendulum is 30o from the vertical,what is the magnitude of the gravitational torque calculated about the pivot
Physics
1 answer:
Alborosie3 years ago
4 0

Hi there!

Recall the equation for Torque:
\large\boxed{\Sigma \tau = rFsin\phi}

In words, the torque is the force multiplied by the distance from the LINE OF ACTION to the PIVOT POINT.

In this instance:

F = Mg = 0.75 · 9.8 = 7.35 N

r = 1.25 m

sin(30) = 0.5

Plug in the values:

\Sigma \tau = (1.25)(7.35)(0.5) = \boxed{4.59 Nm}

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a 0.15 kg baseball has a momentum of 0.78 kg*m/s just before it lands on the ground. What was the ball's speed just before landi
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Unknown:

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Momentum brainly.com/question/9484203

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