Answer:
Electric Field = 3.369 x 10^4 N/C
Explanation:
Radius = r = (r1 + r2) / 2 = (1.6 + 3.6) /2 = 2.6 cm + 2.3 cm = 4.9 cm = 0.049 m
As we know, Electric field = E = kQ/r.r
= 8.98755 x 10^9 x 9 x 10^-9 / 0.049 x 0.049 = 33689.275 N/C
= 3.369 x 10^4 N/C
Speed = 500m/5min = 100 m/min. Direction = west. Velocity = 100 m/min west.
Answer:
Explanation:
Given that,
Capacitance 1, 
Capacitance 2, 
Capacitance 3, 
C₁ and C₂ are connected in series. Their equivalent is given by :
Now C' and C₃ are connected in parallel. So, the final equivalent capacitance is given by :
So, the equivalent capacitance of the combination is 1.97 micro farad. Hence, this is the required solution.
Answer:
i like how your computer thing is red, mine is orange bc i have a haikyuu wallpaper
Explanation:
Answer:
The correct option is;
B) No, the Navy vessel is slower
Explanation:
The speed of some torpedoes can be as high as 370 km/h. The average speed of a fast Navy vessel is approximately 110 km/h
Therefore, the torpedoes travel approximately 3 times as fast as the (slower) Navy vessel, such that the torpedo covers three times the distance of the Navy vessel in the same time and therefore, if the Navy vessel and the torpedo continue in a straight line (in the same direction) due north the vessel can not outrun the torpedo
Therefore, no the Navy vessel travels slower than a torpedo.
