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2 years ago

Please help ill mark brainliest

Mathematics

1 answer:

posledela2 years ago

7 0

Answer:

x = 3

Step-by-step explanation:

since it's hitting 3 on the x axis and just goes up and down where 3 is, all the points have an x of 3 and nothing else. making the equation x = 3

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A company makes and sells charm bracelets. The cost of producing x bracelets is represented by the function

Serggg [28]

P(x) = 12x – 180

Given:

A company makes and sells charm bracelets.

The cost of producing x bracelets is represented by the function C(x) = 180 +

The revenue earned from selling x bracelets is represented by the function

R(x) = 20x.

Explanation of terms:

For x bracelets,

Cost of production is C(x); C(x) = 180 + 8x

Revenue earned is R(x); R(x) = 20x.Profit made is P(x); P(x) is unknown

Profit made = Revenue earned – Cost of production

∴ P(x) = R(x) – C(x)

P(x) = 20x – (180 + 8x)

P(x) = 20x – 180 – 8x

P(x) = 12x – 180

The profit made from selling x bracelets is represented by the function

P(x) = 12x – 180

8 0

3 years ago

Read 2 more answers

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

8 0

2 years ago

NEED THE ANSWER ASAP, PLEASE HELP!! What are the coordinates of the focus of the parabola?

qwelly [4]

Answer:

Vertex is (-8, 4) not one of the answers offered!

Step-by-step explanation:

Factor -1/8 out of the first two terms. Leave a space inside parentheses in which to add a number.

$y=-\frac{1}{8}(x^2 + 16x + \text{-----})-4$

Complete the square by squaring half the coefficient of x and adding it in the space.

$(\frac{16}{2})^2=64$

Add 64 in the space you made, then compensate for that at the end of the expression by subtracting $-\frac{1}{8}(64)=-8$

$y=-\frac{1}{8}(x^2+16x+64)-4+8\\y=-\frac{1}{8}(x+8)^2+4$

The x-coordinate of the vertex is the opposite of +8, the number inside the parentheses. The y-coordinate of the vertex is the number at the end of the expression.

V(-8, 4)

8 0

3 years ago

Prove that P(2,3), (3, 4), R(5, 6) and S(4,5) are the vertices of a rhombus

MatroZZZ [7]

Solution :-

Given coordinates to us are ,

P(2,3) .
Q(3,4).
R(5,6)
S(4,5)

Here it is asked to Prove that these are vertices of Rhombus . So we know that all sides of a Rhombus are equal .So if we show that value of all sides lenght are equal , then it will be a Rhombus .

We will use Distance Formula .

Now , here ,

Distance between P and Q :

⇒ x = √ (2 - 3)² + (3-4)² .

⇒ x = √ (-1)² + (-1)² .

⇒ x = √ 1 + 1 .

⇒ x = √2 .

Distance between Q and S :

⇒ x =√ [ (3-4)² + (5-4)².

⇒x = √ 1² + 1² .

⇒ x = √ 1 + 1 .

⇒ x = √2 .

Similarly we can prove other distances equal.

3 0

3 years ago

Look at the screenshot, please. (no links)

elena-s [515]

Answer: 14

Step-by-step explanation: 18 x 14 = 252

3 0

3 years ago

Read 2 more answers