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3 years ago

Without graphing, determine the range of the function f(x) = 4|x+6|-5 over the interval [-10,5].

Mathematics

1 answer:

spin [16.1K]3 years ago

3 0

Answer:

[-5,39]

Step-by-step explanation:

The vertex is at (-6,-5)

The interval is from -10 to 5 (inclusive of both endpoints...

Absolute function is open up because 4 is positive

I will plug in both endpoints now:

f(-10)=4|-10+6|-5 f(5)=4|5+6|-5

f(-10)=4(4)-5 f(5)=4(11)-5

f(-10)=11 f(5)=39

So the highest reached by f(5) which is 39 so our range will go up to 39 (inclusive)

11 is not the lowest reached, -5 is because our vertex was included within the domain

So the range is [-5,39]

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Which is equivalent to V180x11 after it has been simplified completely?

inna [77]

Question:

Which is equivalent to $\sqrt{180x^{11}}$ after it has been simplified completely?

Answer:

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

Step-by-step explanation:

Given

$\sqrt{180x^{11}}$

Required

Simplify

We start by splitting the square root

$\sqrt{180x^{11}} = \sqrt{180} * \sqrt{x^{11}}$

Replace 180 with 36 * 5

$\sqrt{180x^{11}} = \sqrt{36 * 5} * \sqrt{x^{11}}$

Further split the square roots

$\sqrt{180x^{11}} = \sqrt{36} *\sqrt{5} * \sqrt{x^{11}}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{11}}$

Replace power of x; 11 with 10 + 1

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10 + 1}}$

From laws of indices; $a^{m+n} = a^m * a^n$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x^1}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10} * x}$

Further split the square roots

$\sqrt{180x^{11}} = 6*\sqrt{5} * \sqrt{x^{10}} * \sqrt{x}$

From laws of indices; $\sqrt{a} = a^{\frac{1}{2}}$

So, we have

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{10*\frac{1}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{\frac{10}{2}} * \sqrt{x}$

$\sqrt{180x^{11}} = 6*\sqrt{5} * x^{5} * \sqrt{x}$

Rearrange Expression

$\sqrt{180x^{11}} = 6 * x^{5} * \sqrt{5} * \sqrt{x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5} * \sqrt{x}$

From laws of indices; $\sqrt{a} *\sqrt{b} = \sqrt{a*b} = \sqrt{ab}$

So, we have

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5*x}$

$\sqrt{180x^{11}} = 6x^{5} * \sqrt{5x}$

$\sqrt{180x^{11}} = 6x^{5}\sqrt{5x}$

<em>The expression can no longer be simplified</em>

Hence, $\sqrt{180x^{11}}$ is equivalent to $6x^{5}\sqrt{5x}$

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2 years ago

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If the height of a triangle

Dvinal [7]

Answer:

75 cm

Step-by-step explanation:

To find the area of a traingle you use the following equation

b*h*.5

We know that the height of the triange is three times the base and that the area is 937.5

This means that

b*3b*.5=937.5

We can combine this and get 1.5b^2=937.5

We can then divide by 1.5 to get b by itself

b^2=625

Then take the square root for our answer and get b=25 (while be also can be -25 it doesn't make sense to have a negative answer in the context of this problem)

So we know that b=25 and that h=3b which means that the height is 75 cm

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3 years ago

Billy stacked six pieces of wood on top of one another. If each piece

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The answer would be 175 feet tall

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On the same winter morning, the temperature is -28f in Anchorage,Alaska and 65f in Miami,Florida. How many degrees warmer was it

Xelga [282]

C. 90 degrees warmer

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3 years ago

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Ruth wants to buy a skateboard for $44. She has $100 in her account. She spent $11.36 to buy stationary. She also wants to buy s

djverab [1.8K]

Given :

Ruth wants to buy a skateboard for $44.

She has $100 in her account. She spent $11.36 to buy stationary.

She also wants to buy some comic books for $3.72 each.

To Find :

The maximum number of comic books, n, that Ruth can buy so that she has enough money left to buy the skateboard.

Solution :

Money left after buying skateboard and stationary is :

Money left = $(100 - 11.36 - 44)

Money left = $44.64

Number of comic she can buy is :

$n = \dfrac{44.64}{3.72}\\\\n = 12$

Therefore, she can buy a maximum of 12 books.

Hence, this is the required solution.

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