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lukranit [14]
2 years ago
15

How can you write and evaluate numbers with exponents?

Mathematics
2 answers:
deff fn [24]2 years ago
7 0

Answer:

You can use the order of operations to evaluate the expressions containing exponents. First, evaluate anything in Parentheses or grouping symbols. Next, look for Exponents, followed by Multiplication and Division (reading from left to right), and lastly, Addition and Subtraction (again, reading from left to right). this is personally my fav way to do it

jarptica [38.1K]2 years ago
5 0

Answer:

______________________________

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Find the area of the figure
sweet [91]

Answer:

400 square yards

Step-by-step explanation:

square part = l x w = 20 x 15 = 300

triangle part = 1/2 b x h = 1/2 (20) (10) = 100

300 + 100 = 400

3 0
3 years ago
Need help I don’t know how to do it
liberstina [14]
First attempt to break the top portion up so the negative signs don’t confuse you.

(2 x -2) x (-2 x -4)/ 2 x 2

= (-4) x (8)/ 4

= -32/4

= -8

*Remember that multiplying two negative numbers give you a positive number
8 0
2 years ago
HELP ME PLZ !!! IT'S ALGEBRA
Drupady [299]

Answer:

x = - 8/23

y = 40/23

Step-by-step explanation:

-5x- y = 0

and

-8x+3y = 8

The first step to solve this would be to get what one of the two variables equal. The easiest in this case is y from the first equation.

-5x-y = 0

-y = 5x

y = - 5x

Now you can take this y value and plug it into the section equation.

-8x + 3(-5x) = 8

-8x - 15x = 8

-23x = 8

x = - (8/23)

Once you get the x value you can plug it back into equation one to get y's value

-5*-(8/23)  - y = 0

40/23 - y = 0

y = 40/23

3 0
3 years ago
Let X be the mean of a random sample of size n = 64 from the uniform distribution on the interval (0, 3), i.e. f(x) = ( 1 3 , 0
allochka39001 [22]

Answer:

P ( 1.2 < X < 2.1 ) = 0.3

Step-by-step explanation:

Given:

Uniform distribution over interval (0,3) can be modeled by a probability density function f(x)

f(x) = 1 / (b - a)

Where a < x < b is the domain at which function is defined:

f(x) = 1 / (3) = 1 / 3

Where, X - U ( u , δ )

u = ( a + b ) / 2 = (0 +3) / 2 = 1.5

δ = ( b - a ) / sqrt (12) = (3 - 0) / sqrt (12) = 0.866

Hence,

X - U ( 1.5 , 0.866 )

There-fore calculating P ( 1.2 < X < 2.1 ):

P ( 1.2 < X < 2.1 ) = \int\limits^b_a{f(x)} \, dx

Where, a = 1.2 and b = 2.1

P ( 1.2 < X < 2.1 ) = x / 3 |

P ( 1.2 < X < 2.1 ) = 2.1 /3 - 1.2 / 3 = 0.3

Answer: P ( 1.2 < X < 2.1 ) = 0.3

6 0
3 years ago
Match each number on the left with the correct description of the number on the right.
7nadin3 [17]

Answer:

I hope this helps you

:)

5 0
2 years ago
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