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bezimeni [28]
3 years ago
15

Rewrite as a simplified fraction.

Mathematics
1 answer:
Contact [7]3 years ago
3 0

Answer: Hi I think that I can help you with your problem!

Let  which means

Here a bar over 8 means that there the given decimal value is non terminating and there are a large numbers of 8 present after the decimal.

To solve the given non terminating decimal as fractions, we will have to eliminate the bar term from the given value.

So, we can rewrite  as:

......(1)

Now, let us multiply the above with 10.

....... (2)

Now, let us subtract (1) from (2):

So, in simplified fractions:

Step-by-step explanation:

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3(-6+2)
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Which expression can be used to check the answer to 56+(-14)=n?
Delvig [45]

Answer: n = 42

Step-by-step explanation:

56 - 14 = 42

If + and - are right next to each other, the + cancels out.

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I need fast help with step by step<br> <img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5E2_1%20%7B%5Cfrac%7B3x-1%7D%7Bx%2B1%7D
Ganezh [65]

Answer:

1.38 to the nearest hundredth.

Step-by-step explanation:

Dividing:

x + 1 ) 3x - 1 ( 3            

          3x + 3

                -4

so (3x - 1) / (x + 1) =  3  - 4 / x+ 1

Integral  of (3  - 4 / x+1 )  = 3x - 4 ln(x + 1)

Between  limits of 1 and 2 we have:

(3(2) - 4 ln 3) - (3 - 4 ln2)

=  1.6056 - 0.2274

= 1.3782.

5 0
4 years ago
What are three different ways to write 15,638 with only hundreds, tens, and ones?
saul85 [17]
Fifteen thousand six-hundred and thirty-eight
5 0
3 years ago
SHOE COLLECTION: Marquise, Bron'Tavious, and JayDarius each have a shoe collection of Nike Air Vapor Max shoes. Marquise has two
Natasha_Volkova [10]

Answer:

(a) The number of shoes that Marquise has is 40 pairs of shoes

(b) The number of pairs of shoes that Bron'Tavious has is 20 pairs of shoes

(c) The number of pairs of shoes that JayDarius has is 35 pairs of shoes

Step-by-step explanation:

The given information are;

The number of shoes that Marquise has = 2 × The number of pairs of shoes that Bron'Tavious

The number of pairs of shoes that JayDarius has = The number of pairs of shoes that Bron'Tavious + 15

The total number of pairs of shoes they have all together = 95 pairs of shoes

Let the number of pairs of shoes that Bron'Tavious has = X. Therefore, we have;

The number of shoes that Marquise has = 2 × X

The number of pairs of shoes that JayDarius has = X + 15

The total number of pairs of shoes they have all together = X + X + 15 + 2 × X = 95

X + X + 15 + 2 × X = 95

4 × X + 15 = 95

4 × X = 95 - 15 = 80

X = 80/4 = 20

∴ X = 20

(a) The number of shoes that Marquise has = 2 × X = 2 × 20 = 40

The number of shoes that Marquise has = 40 pairs of shoes

(b) The number of pairs of shoes that Bron'Tavious has = X = 20

The number of pairs of shoes that Bron'Tavious has = 20 pairs of shoes

(c) The number of pairs of shoes that JayDarius has = X + 15 = 20 + 15 = 35

The number of pairs of shoes that JayDarius has = 35 pairs of shoes.

5 0
3 years ago
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