3 years ago

What is the value of x in the equation 3/2(4x – 1) – 3x = 5/4 – (x + 2)?

Mathematics

1 answer:

Olegator [25]3 years ago

5 0

i have attached a file you can see it from there.

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A department store sells a pair of shoes with an 87% markup. If the store bought the pair of shoes for $55.25, what is the selli

kolbaska11 [484]

Markup means they sell it for that percentage more than they bought it for. First let's calculate how much they will mark it up for:

$\sf 55.25\cdot 87\%$

Convert 87% into a decimal(87/100):

$\sf 55.25\cdot 0.87$

Multiply:

$\sf\approx 48$

This is how much they'll mark it up, now let's add it to how much they bought it for to find out the selling price:

$\sf 48+55.25\approx\boxed{\sf \$ 103}$

5 0

2 years ago

What is the volume of a box with a height of 3/2 inches, a length of 7/2 inches, and a width of 5/2 inches.

JulsSmile [24]

Answer:

13.125 cubic inches

Step-by-step explanation:

Volume of box is 3/2 X 7/2 X 5/2 = 105/8 = 13 1/8 = 13.125 cubic inches

4 0

3 years ago

Convert the rectangular coordinates (-9, 3V3) into polar form. Express the angle

Whitepunk [10]

Answer:

$(6\sqrt{3},\,\frac{5\pi}{6})$

Step-by-step explanation:

The radius r can be found from the relationship

$r^2=x^2+y^2\\r^2=(-9)^2+(3\sqrt{3})^2\\r^2=81+27=108\\r=\sqrt{108}\\r=6\sqrt{3}$

The point is in Quadrant II (-, +), so use the inverse cosine function to find the angle.

$\cos{\theta}=\frac{x}{r}=\frac{-9}{6\sqrt{3}}\\\cos{\theta}=-\frac{9}{6\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}\\\cos{\theta}=-\frac{9\sqrt{3}}{6\cdot3}\\\cos{\theta}=-\frac{\sqrt{3}}{2}\\\\\cos^{-1}\frac{-\sqrt{3}}{2}}=\frac{5\pi}{6}$