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3 years ago

12

chad has 22 coins in his pocket, all of which are dimes and quarters. if the total value of his change is 460 cents, how many di

mes and how many quarters does he have?

1 answer:

Alenkinab [10]3 years ago

6 0

Answer: delete this plz

Step-by-step explanation:

You might be interested in

Omg pls help ill give you 20 points

ElenaW [278]

Answer:

Step-by-step explanation:

Amount of water in tank 1 = amount of water in tank 2

30t +25 = -20t + 1000

Add 20t to both sides

30t + 20t + 25 = -20t + 20t + 1000

50t + 25 = 1000

Subtract 25 from both sides

50t + 25 - 25 = 1000 - 25

50t = 975

Divide both sides by 50

t = 975/50 = 39/2

$= 19 \frac{1}2}$

t = 19 minutes 30 seconds

After 19 1/2 minutes both tanks will have 610 liters of water

5 0

2 years ago

Two linear equations are shown. A coordinate grid with 2 lines. The first line is labeled y equals StartFraction one-third EndFr

Lorico [155]

Answer:

$(7,\frac{13}{3})$

Step-by-step explanation:

we have

<em>The equation of the first line</em>

$y=\frac{1}{3}x+2$ ------> equation A

<em>The equation of the second line</em>

$y=\frac{4}{3}x-5$ ------> equation B

Solve the system of equations by elimination

Multiply equation A by -4 both sides

$(-4)y=(-4)(\frac{1}{3}x+2)$

$-4y=-\frac{4}{3}x-8$ --------> equation C

Adds equation B and equation C

$y=\frac{4}{3}x-5\\-4y=-\frac{4}{3}x-8\\--------\\y-4y=-5-8\\-3y=-13\\y=\frac{13}{3}$

<em>Find the value of x</em>

substitute the value of y

$\frac{13}{3}=\frac{1}{3}x+2$

$\frac{1}{3}x=\frac{13}{3}-2$

Multiply by 3 both sides

$x=13-6$

$x=7$

therefore

The solution to the system of equations is the point $(7,\frac{13}{3})$

5 0

2 years ago

Read 2 more answers

A bag of crisps weighs 42g. Sam ate two thirds of the bag.<br> How many grams were left? Help please

slega [8]

Answer:

I think the answer is 14 grams correct me if i'm wrong hope this helps :)

Step-by-step explanation:

8 0

3 years ago

Pioneer company has given an aptitude test to 71 potential job applicants. The test score had an average of 81 and a standard de

Agata [3.3K]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

In point A:

$\to df = n - 1 = 71-1= 70$

In point B:

$\to t = \frac{(x -X)}{s} = \frac{(93-81)}{8} = \frac{12}{8}= 1.5$

In point C:

For df = 70, the top 5% critical t score

tcrit = 1.666914479

Thus,

$\to 1.666914479 = \frac{(x - 81)}{8}\\\\\to 1.666914479 \times 8 = (x - 81)\\\\\to 13.335315832 = (x - 81)\\\\\to 13.335315832 +81 =x \\\\\to x= 94.335315832$

In point D:

For df = 70, the top 5% critical t score

tcrit = -1.666914479

$\to -1.666914479 = \frac{(x - 81)}{8}\\\\\to -1.666914479 \times 8= (x - 81)\\\\\to -13.335315832= (x - 81)\\\\\to -13.335315832+81 = x \\\\\to x = 67.664684168\\\\$

In point E:

The lower cutoff is 0.10 in the center, which would be around 80 %. The critical point therefore is

tcrit = -1.293762898

$\to -1.293762898 = \frac{(x-81)}{8}\\\\\to -1.293762898 \times 8= (x-81) \\\\\to -1.293762898 \times 8= (x-81) \\\\\to -10.350103184=x-81\\\\\to -10.350103184+81=x\\\\\to x=70.649896816$

In point F:

The lower cutoff is 0.90 in the center, which would be around 80 %. The critical point therefore is

tcrit = 1.293762898

$\to 1.293762898 = \frac{(x-81)}{8}\\\\\to 1.293762898 \times 8= x-81\\\\\to 10.350103184 =x-81\\\\\to 10.350103184 +81=x\\\\\to x = 91.350103184\\$

5 0

3 years ago

Solve for y in the equation -y+9=23

timurjin [86]

Answer:

y=-14

Step-by-step explanation:

-y+9=23

-y=14

y=-14

7 0

3 years ago