The length of the shorter rope is 20 cm.
<h3>How to find the original length of the rope using ratio?</h3>
He cut a rope into two pieces with lengths having a ratio of 5 to 2.
The shorter piece is 70 cm long.
The length of the original rope can be calculated as follows:
The ratio of the length of the rope is as follows;
5 : 2
let
x = length of the original rope
Therefore,
length of shorter piece = 2 / 7 × 70
length of shorter piece = 2 / 7 × 70
length of shorter piece = 140 / 7
length of shorter piece = 20 cm
Therefore, the length of the shorter rope is 20 cm.
learn more on ratio here: brainly.com/question/15418103
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Answer:
cos(52°) = 18/x
x = 18·sec(52°)
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you that ...
Cos = Adjacent/Hypotenuse
In this geometry, that means ...
cos(52°) = 18/x
You can use the relation sec(x) = 1/cos(x) to rewrite this as ...
x = 18·sec(52°)
_____
You can also use the complementary angle and the complementary trig function.
sin(90° -52°) = 18/x
The answer is 7/20. 1/4= 5/20 and 3/5 = 12/20
What I did was find the GCF (greatest common factor) of both 4 and 5 which was 20. Then I multiplied both numerators by the same number I multiplied the denominator with. Afterwards I subtracted both numerators (12-5) and this equals to 7
Hope that helps
