Answer:
None of the options is the answer to the question
Step-by-step explanation:
we know that
The equation of a vertical parabola into vertex form is equal to

where
(h,k) is the vertex of the parabola
case A) we have

In this case the x-coordinate of the vertex will be negative
therefore
case A is not the solution
case B) we have

This case is a vertical parabola open downward (the vertex is a maximum)
The vertex is the point
<u>but is not a minimum</u>
see the attached figure
therefore
case B is not the solution
case C) we have

Convert into vertex form
Group terms that contain the same variable, and move the constant to the opposite side of the equation

Complete the square. Remember to balance the equation by adding the same constants to each side


Rewrite as perfect squares

--------> vertex form
The vertex is the point 
therefore
case C is not the solution
case D) we have
Convert into vertex form
Group terms that contain the same variable, and move the constant to the opposite side of the equation

Factor the leading coefficient
Complete the square. Remember to balance the equation by adding the same constants to each side


Rewrite as perfect squares

--------> vertex form
The vertex is the point 
therefore
case D is not the solution
The answer to the question will be the function
