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lubasha [3.4K]
3 years ago
6

this reading selection is a special kind of advertisement called a... a.diagram b.flier c.menu d.fhoto please answer

Mathematics
1 answer:
eimsori [14]3 years ago
7 0
Probably b. flyer

Of course, it's tough to tell without the selection.

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A rope 40m long is used to form a rectangle. If the length of the rectangle formed is 4m longer than the width. Calculate the ar
ivanzaharov [21]

Answer:

96 sq. m

Step-by-step explanation:

If the width is x, the length is x + 4 and since perimeter = 2 * (length + width), we can write:

40 = 2(x + x + 4)

40 = 2(2x + 4)

20 = 2x + 4

16 = 2x

x = 8 so x + 4 = 12, therefore the area is 8 * 12 = 96 square meters.

5 0
2 years ago
Read 2 more answers
A pizza parlor offers 3 sizes of pizzas, 2 types of crust, and one of 4 different toppings. How many different pizzas can be mad
KonstantinChe [14]

Answer:  The total number of  pizzas that can be made from the given choices is 24.

Step-by-step explanation:  Given that a pizza parlor offers 3 sizes of pizzas, 2 types of crust, and one of 4 different toppings.

We are to find the number of different pizzas that can be made from the given choices.

We have the <em><u>COUNTING PRINCIPLE :</u></em>

If we have m ways of doing one task and n ways of doing the second task, then the number of ways in which we can do both the tasks together is m×n.

Therefore, the number of different pizzas that can be made from the given choices is

N=3\times2\times4=24.

Thus, the total number of  pizzas that can be made from the given choices is 24.

5 0
3 years ago
How to write five and nine tenths in standard from
Trava [24]
5 9/10 .........................................
3 0
2 years ago
Grace wants to find the probability of a family of 3 children having 2 boys and 1 girl. Use a tree diagram to list the possibili
pychu [463]

Answer:

Step-by-step explanation:

My approach was to draw out the probabilities, since we have 3 children, and we are looking for 2 boys and 1 girl, the probabilities can be Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy. So a 2/3 chance if you think about it, your answer 2/3 can't be correct. If we assume that boys and girls are born with equal probability, then the probability to have two girls (and one boy) should be the same as the probability to have two boys and one girl. So you would have two cases with probability 2/3, giving an impossible 4/3 probability for both cases. Also, your list "Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy" seems strange. All of those are 2 boys and 1 girl, so based on that list, you should get a 100 percent chance. But what about Boy-Girl-Girl, or Girl-Girl-Girl? You get 2/3 if you assume that adjacencies in the (ordered) list are important, i.e., "2 boys and a girl" means that the girl was not born between the boys.

5 0
1 year ago
Let f(x) = 8x3 − 28x + 61 and g(x) = 2x + 5. Find f of x over g of x.
antoniya [11.8K]

Answer:

4x^2-10x+11+\frac{6}{2x+5}

Step-by-step explanation:

The given functions are:

f(x)=8x^3-28x+61 and g(x)=2x+5

By algebraic properties of functions;

\frac{f(x)}{g(x)}=\frac{8x^3-28x+61}{2x+5}

We perform the long division of the two polynomials as shown in the attachment.

Therefore:

\frac{8x^3-28x+61}{2x+5}=4x^2-10x+11+\frac{6}{2x+5}

The last choice is correct

8 0
2 years ago
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