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lana66690 [7]
2 years ago
6

HELPPPP PLSSSSSSSSSSSSSSS

Mathematics
2 answers:
muminat2 years ago
5 0
1.67 meters, I did this test thing. Have a good day/night
Alexus [3.1K]2 years ago
4 0

Answer:

1.67 meters!

Step-by-step explanation:

First, we can start out by converting centimeters to meters. There are 100 centimeters in a meter, therefore to convert centimeters to meters we divide by 100. 17/100=0.17. Then, to figure out how tall Felicidad was last year, we must work backward, and subtract (because when you grow, you add). 1.84 meters- 0.17 meters= 1.67 meters!

Hope this helped!

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Answer:

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Step-by-step explanation:

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3 years ago
What is the difference?
Crazy boy [7]

Answer:

<h2>D. \frac{x^{2}+3x-12 }{(x-5)(x+3)(x+7)} \\ or StartFraction x squared + 3 x minus 12 Over (x + 3) (x minus 5) (x + 7) EndFraction</h2>

Step-by-step explanation:

Given the expression \frac{x}{x^{2}-2x-15 } - \frac{4}{x^{2} + 2x - 35 }, the dfference is expressed as follows;

Step1: First we need to factorize the denominator of each function.

\frac{x}{x^{2}-2x-15 } - \frac{4}{x^{2} + 2x - 35 }\\= \frac{x}{x^{2}-5x+3x-15 } - \frac{4}{x^{2} + 7x-5x - 35 }\\= \frac{x}{x(x-5)+3(x-5) } - \frac{4}{x( x+ 7)x-5(x +7) }\\= \frac{x}{(x-5)(x+3) } - \frac{4}{(x-5)(x +7) }\\\\

Step 2: We will find the LCM of the resulting expression

=  \frac{x}{(x-5)(x+3) } - \frac{4}{(x-5)(x +7) }\\= \frac{x(x+7)-4(x+3)}{(x-5)(x+3)(x+7)} \\= \frac{x^{2}+7x-4x-12 }{(x-5)(x+3)(x+7)} \\= \frac{x^{2}+3x-12 }{(x-5)(x+3)(x+7)} \\

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8 0
3 years ago
A commercial aircraft gets the best fuel efficiency if it operates at a minimum altitude of 29,000 feet and a maximum altitude o
natita [175]

Answer:

x\geq 29,000  and  x\leq 41,000

Step-by-step explanation:

Let

x -----> the altitude of a commercial aircraft

we know that

The expression " A minimum altitude of 29,000 feet" is equal to

x\geq 29,000

All real numbers greater than or equal to 29,000 ft

The expression " A maximum altitude of 41,000 feet" is equal to

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All real numbers less than or equal to 41,000 ft

therefore

The compound inequality is equal to

x\geq 29,000  and  x\leq 41,000

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