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LUCKY_DIMON [66]
2 years ago
9

-9+z=26 pls show work ‼️ ty

Mathematics
2 answers:
vovikov84 [41]2 years ago
4 0

Answer:

z = 35

Step-by-step explanation:

-9 + z = 26

Add 9 on both sides to leave the z alone

z = 35

You can verify this by adding 35 into -9 which leads you to the answer: 26

V125BC [204]2 years ago
4 0

Answer:

Step-by-step explanation:

Rearrange terms

-9+ z =26 to z - 9=26

Add 9 to both sides

z - 9 + 9 = 26 + 9

Simplify

-9+9=0

26+9=35

x=35

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Answer:

5 weeks

Step-by-step explanation:

Let's find how much money she saves a week by multiplying the decimal form of 60% and $70.

To get the decimal form of a percent you have to move the decimal to the left twice, like this: 60 ---> .60

Now that we have the decimal form of the percent we can multiply it by the 70 to find how much she saves a week:

(70)(.6) = 42

Therefore, Kendra saves $42 each week.

To find how many weeks it will take Kendra to buy the game system you divide $210 by the $42. Like this:

(210)/(42) = 5

All in all, it will take Kendra 5 weeks to save enough money to buy a game system that costs $210.

<em>I hope this helps!!</em>

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3 years ago
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1 2 3 4 5 6 7 8 9 10 TIME REMAINING 54:32 Because the lid of a marker is wider than the marker itself, a set of markers can be p
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Answer:

10 Square Inches

Step-by-step explanation:

<u>Trapezoid</u>

Base =12 inches

Height =10 inches

Top side= 10 inches.

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Base = 12 inches

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3 years ago
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Because of safety considerations, in May 2003 the Federal Aviation Administration (FAA) changed its guidelines for how small com
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Answer:

a) The 95% confidence interval for the mean summer weight (including carry-on luggage) of Frontier Airlines passengers is between 179 and 187 pounds. This means that we are 95% sure that the mean summer weight of all Frontier Airlines passengers is between these two values.

b)

The 95% confidence interval for the mean winter weight (including carry-on luggage) of Frontier Airlines passengers is between 185.4 pounds and 194.6 pounds. This means that we are 95% sure that the mean winter weight of all Frontier Airlines passengers is between these two values.

c) They are respected, as the upper bound of both intervals is below the new FAA recommendations.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve these questions.

Question a:

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 100 - 1 = 99

95% confidence interval

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M = T\frac{s}{\sqrt{n}} = 1.9842\frac{20}{\sqrt{100}} = 4

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Question b:

Critical value is the same(same sample size and confidence level).

The margin of error is:

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The lower end of the interval is the sample mean subtracted by M. So it is 190 - 4.6 = 185.4 pounds.

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c. The new FAA recommendations are 190 pounds for summer and 195 pounds for winter. Comment on these recommendations in light of the confidence interval estimates from Parts (a) and (b).

They are respected, as the upper bound of both intervals is below the new FAA recommendations.

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