That water has a greater freezing point then gasoline
Answer:
you can move 6 spaces and the most common number you can get is a 1 or a four
Step-by-step explanation:
<h2>
Answer:</h2>
A pyramid is a polyhedron where the base is a polygon and whose lateral faces are all triangles. So a triangular pyramid is a pyramid that has a triangular base. The definition of a solid tells us that this is a three-dimensional shape. The figure below shows a triangular pyramid, so you can see that:
- This triangular pyramid has 4 faces
- The solid has 3 side faces and all are triangles
- The base is also a triangle
- This pyramid has 4 vertices
- It has 6 edges
Answer:
D
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
The square oh the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
h² = (9
)² + (9
)² = 162 + 162 = 324 ( take the square root of both sides )
h =
= 18 → D
![\bf \qquad \qquad \textit{ratio relations} \\\\ \begin{array}{ccccllll} &Sides&Area&Volume\\ &-----&-----&-----\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array} \\\\ -----------------------------\\\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\ -------------------------------](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Cqquad%20%5Ctextit%7Bratio%20relations%7D%0A%5C%5C%5C%5C%0A%5Cbegin%7Barray%7D%7Bccccllll%7D%0A%26Sides%26Area%26Volume%5C%5C%0A%26-----%26-----%26-----%5C%5C%0A%5Ccfrac%7B%5Ctextit%7Bsimilar%20shape%7D%7D%7B%5Ctextit%7Bsimilar%20shape%7D%7D%26%5Ccfrac%7Bs%7D%7Bs%7D%26%5Ccfrac%7Bs%5E2%7D%7Bs%5E2%7D%26%5Ccfrac%7Bs%5E3%7D%7Bs%5E3%7D%0A%5Cend%7Barray%7D%20%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0A%5Ccfrac%7B%5Ctextit%7Bsimilar%20shape%7D%7D%7B%5Ctextit%7Bsimilar%20shape%7D%7D%5Cqquad%20%5Ccfrac%7Bs%7D%7Bs%7D%3D%5Ccfrac%7B%5Csqrt%7Bs%5E2%7D%7D%7B%5Csqrt%7Bs%5E2%7D%7D%3D%5Ccfrac%7B%5Csqrt%5B3%5D%7Bs%5E3%7D%7D%7B%5Csqrt%5B3%5D%7Bs%5E3%7D%7D%5C%5C%5C%5C%0A-------------------------------)

the ratio of the cost, is tandem to the ratio of the areas, because, to get the cost for the mulch, you have to first know how many square meters/feet have, and then you apply the cost evenly, now, the cost is just a factor, therefore, the ratio is retained.