It can lead to deadly changes.
Using compound interest, it is found that the approximate difference in the number of years that calvin and makayla have their money invested is given as follows:
Makayla invests her money 2 years longer.
<h3>What is compound interest?</h3>
The amount of money earned, in compound interest, after t years, is given by:
![A(t) = P\left(1 + \frac{r}{n}\right)^{nt}](https://tex.z-dn.net/?f=A%28t%29%20%3D%20P%5Cleft%281%20%2B%20%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D)
In which:
- A(t) is the amount of money after t years.
- P is the principal(the initial sum of money).
- r is the interest rate(as a decimal value).
- n is the number of times that interest is compounded per year.
- t is the time in years for which the money is invested or borrowed.
For Calvin, the parameters are given as follows:
![P = 400, r = 0.05, n = 12, A(t) = 658.8](https://tex.z-dn.net/?f=P%20%3D%20400%2C%20r%20%3D%200.05%2C%20n%20%3D%2012%2C%20A%28t%29%20%3D%20658.8)
Hence:
![A(t) = P\left(1 + \frac{r}{n}\right)^{nt}](https://tex.z-dn.net/?f=A%28t%29%20%3D%20P%5Cleft%281%20%2B%20%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D)
![658.8= 400\left(1 + \frac{0.05}{12}\right)^{12t}](https://tex.z-dn.net/?f=658.8%3D%20400%5Cleft%281%20%2B%20%5Cfrac%7B0.05%7D%7B12%7D%5Cright%29%5E%7B12t%7D)
![\left(1 + \frac{0.05}{12}\right)^{12t} = \frac{658.8}{400}](https://tex.z-dn.net/?f=%5Cleft%281%20%2B%20%5Cfrac%7B0.05%7D%7B12%7D%5Cright%29%5E%7B12t%7D%20%3D%20%5Cfrac%7B658.8%7D%7B400%7D)
![(1.00416666667)^{12t} = 1.647](https://tex.z-dn.net/?f=%281.00416666667%29%5E%7B12t%7D%20%3D%201.647)
![\log{(1.00416666667)^{12t}} = \log{1.647}](https://tex.z-dn.net/?f=%5Clog%7B%281.00416666667%29%5E%7B12t%7D%7D%20%3D%20%5Clog%7B1.647%7D)
![12t\log{1.00416666667} = \log{1.647}](https://tex.z-dn.net/?f=12t%5Clog%7B1.00416666667%7D%20%3D%20%5Clog%7B1.647%7D)
![t = \frac{\log{1.647}}{12\log{1.00416666667}}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B%5Clog%7B1.647%7D%7D%7B12%5Clog%7B1.00416666667%7D%7D)
![t = 10](https://tex.z-dn.net/?f=t%20%3D%2010)
For Makayla, the parameters are given as follows:
![P = 300, r = 0.06, n = 4, (t) = 613.4](https://tex.z-dn.net/?f=P%20%3D%20300%2C%20r%20%3D%200.06%2C%20n%20%3D%204%2C%20%28t%29%20%3D%20613.4)
Hence:
![A(t) = P\left(1 + \frac{r}{n}\right)^{nt}](https://tex.z-dn.net/?f=A%28t%29%20%3D%20P%5Cleft%281%20%2B%20%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D)
![613.4 = 300\left(1 + \frac{0.06}{4}\right)^{4t}](https://tex.z-dn.net/?f=613.4%20%3D%20300%5Cleft%281%20%2B%20%5Cfrac%7B0.06%7D%7B4%7D%5Cright%29%5E%7B4t%7D)
![\left(1 + \frac{0.06}{4}\right)^{4t} = \frac{613.4}{300}](https://tex.z-dn.net/?f=%5Cleft%281%20%2B%20%5Cfrac%7B0.06%7D%7B4%7D%5Cright%29%5E%7B4t%7D%20%3D%20%5Cfrac%7B613.4%7D%7B300%7D)
![(1.015)^{4t} = 2.0447](https://tex.z-dn.net/?f=%281.015%29%5E%7B4t%7D%20%3D%202.0447)
![\log{(1.015)^{12t}} = \log{2.0447}](https://tex.z-dn.net/?f=%5Clog%7B%281.015%29%5E%7B12t%7D%7D%20%3D%20%5Clog%7B2.0447%7D)
![12t\log{1.015} = \log{2.0447}](https://tex.z-dn.net/?f=12t%5Clog%7B1.015%7D%20%3D%20%5Clog%7B2.0447%7D)
![t = \frac{\log{2.0447}}{4\log{1.015}}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B%5Clog%7B2.0447%7D%7D%7B4%5Clog%7B1.015%7D%7D)
![t = 12](https://tex.z-dn.net/?f=t%20%3D%2012)
12 - 10 = 2, hence Makayla invests her money 2 years longer.
More can be learned about compound interest at brainly.com/question/25781328
From the Capillaries blood passes into VENULES then into veins to return to the heart
Answer:
No
Explanation:
The oxygen atoms aren't in the products of the reaction.