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docker41 [41]
2 years ago
11

Find the slope of the line that passes through (6, 7) and (3, 9).

Mathematics
1 answer:
Karolina [17]2 years ago
5 0

Answer:

-2/3

Step-by-step explanation:

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What is the value of the expression (81 1/4) ^4
Mama L [17]

the answer is 43580627.44 according to my calculations!

8 0
3 years ago
(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop
zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})

Compute the sample sizes as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}

       n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}

          =\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

\hat p_{1}=0.45\\\hat p_{2}=0.58

Compute the sample size as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}

       n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}

          =\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666

Thus, the sample sizes are 6666.

7 0
2 years ago
What is the absolute value of -6?
qaws [65]

Answer:

6

Step-by-step explanation:

The absolute value of a non-negative number is the same number.

Example: The absolute value of 4 is 4.

If a number is negative, its absolute value is the same number, without the negative sign.

Example: The absolute value of -3 is 3.

6 0
2 years ago
Read 2 more answers
Is it reasonable if so or if not tell me the equation
lianna [129]
His answer is not reasonable because 5/8>4/3
8 0
2 years ago
F (×)=-4×^2-3 g (×)-3×-3 Find f (4)and g(5)
Elena-2011 [213]
F(4)= -64-3=-69 g(5)= -15-3=-18
3 0
2 years ago
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