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2 years ago

In the triangle below, 4/5 represents which ratio?

Mathematics

2 answers:

ASHA 777 [7]2 years ago

8 0

Answer:
sin (C)

Explanation:
In a right-angled triangle, special trig functions can be applied. These functions are as follows:
sin (theta) = $\frac{opposite}{hypotenuse}$

cos (theta) = $\frac{adjacent}{hypotenuse}$

tan (theta) = $\frac{opposite}{adjacent}$ 

Now, let's check the triangle we have:
We have two options:
First option:
5 is the hypotenuse of the triangle
4 is the side adjacent to angle B
Therefore, we can apply the cos function:
cos (B) = $\frac{4}{5}$ 

Second option:
5 is the hypotenuse of the triangle
4 is the side opposite to angle C
Therefore, we can apply the sin function:
sin (C) = $\frac{4}{5}$

Among the two options, the second one is the one found in the choices. Therefore, it will be the correct one.

Hope this helps :)

Klio2033 [76]2 years ago

6 0

Answer:

Step-by-step explanation:

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The scatter plot below represents the amount of dog food a brand recommends

Dennis_Churaev [7]

Answer:

positive linear association

Step-by-step explanation:

the slope is positive so the linear association is also positive and linear mean generaly in a line not on a curve like a nonlinear assciation.

6 0

2 years ago

P and Q are two points on the line x - y + 1 = 0 and are at distance 5 from the origin. Find the area of the triangle OPQ.

Alecsey [184]

Answer:

P and Q are two points on the line x-y+1=0 and are at a distant of 5 units from the origin. Find the area of triangle POQ.

Step-by-step explanation:

P and Q are the intersection points of

x-y+1 = 0 and the circle x^2 + y^2 = 25

sub y = x+1 into the circle

x^2 + (x+1)^2 = 25

x^2 + x^2 + 2x + 1 - 25 = 0

x^2 + x - 12 = 0

(x+4)(x-3) = 0

x = 3 or x = -4

y = 4 or y = -3

so P(3,4) and Q(-4,3) are our two points

Height of triangle.

h = |0 - 0 + 1|/√2 = 1/√2

PQ = √( (-7)^2 + 1^2) = √50 = 5√2

area POQ = (1/2)(1/√2)(5√2) = 5/2 square units

hope this helped

7 0

1 year ago

Write an equation of the line containing the point (3,5) and perpendicular to the line 4x-3y=5

ICE Princess25 [194]

Answer:

Step-by-step explanation:

In order to write the equation of the line perpendicular to the given line, we first have to know what the slope of the given line is, and there's no way to tell by looking at it in its current form, which is standard. We need to solve that equation for y to determine the slope of that line. Solving for y:

$-3y=-4x+5$ and

3y = 4x - 5 (just change all the signs so our y term isn't negative anymore...yes, you're "allowed" to do that!) and

$y=\frac{4}{3}x-\frac{5}{3}$ So we can see now that the slope of this line is 4/3. That means that the perpendicular slope is -3/4. Passing through the given point (3, 5):