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2 years ago

A train moves from rest to a speed of 25 m/s in 30.0 seconds. What is its acceleration?

Mathematics

1 answer:

12345 [234]2 years ago

6 0

Answer:

$a=0.8\bar{3}m/s^2$

Step-by-step explanation:

$a=\frac{v}{t} \\a=\frac{25m/s}{30s}\\ \\a=0.8\bar{3}m/s^2$

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A middle school took all of its 6th grade students on a field trip to see a play. The students filled 660 seats, which was 55% o

Elan Coil [88]

Answer:

1200 seats

Step-by-step explanation:

x = 660

100 55

55x = 66,000

x = 1200

7 0

3 years ago

Solve the linear equation for x. –4.8(6.3x – 4.18) = –58.56 x =

liq [111]

Answer:

X=2.6

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

Read 2 more answers

Answer quickly please

BigorU [14]

Answer:

Step-by-step explanation:

5 0

2 years ago

Determine the next three terms in the following sequence: ____, ____, ____,...

user100 [1]

Idk I have tried and failed miserably

4 0

2 years ago