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Inga [223]
3 years ago
9

A train moves from rest to a speed of 25 m/s in 30.0 seconds. What is its acceleration?

Mathematics
1 answer:
12345 [234]3 years ago
6 0

Answer:

a=0.8\bar{3}m/s^2

Step-by-step explanation:

a=\frac{v}{t}  \\a=\frac{25m/s}{30s}\\ \\a=0.8\bar{3}m/s^2

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(5 - 7i)(8 + i)
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Answer:

(5 - 7i)(8 + i)

F) 40 - 561

H) 37 - 371

K) -16 - 2i

G) -33 - 61i

J) 47 - 51i

- 9 below

Step-by-step explanation:

7 0
2 years ago
Please help I'm having a small brain moment
ahrayia [7]

Answer:

Option 4: r ≥ 6

Step-by-step explanation:

5(6+3r) + 7 ≥ 127

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37 + 15r ≥ 127

15r ≥ 90

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5 0
3 years ago
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3 years ago
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klio [65]
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4 0
3 years ago
Read 2 more answers
PLEASE HELPPPPP
dsp73

Answer:

see explanation

Step-by-step explanation:

the equation of parabola in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier.

here (h, k ) = (3, 1 ) , then

y = a(x - 3)² + 1

to find a substitute any other point on the graph into the equation.

using (0, 7 )

7 = a(0 - 3)² + 1 ( subtract 1 from both sides )

6 = a(- 3)² = 9a ( divide both sides by 9 )

\frac{6}{9} = \frac{2}{3} = a

y = \frac{2}{3} (x - 3)² + 1 ← in vertex form

------------------------------------------------------

the equation of a parabola in factored form is

y = a(x - a)(x - b)

where a, b are the zeros and a is a multiplier

here zeros are - 1 and 3 , the factors are

(x - (- 1) ) and (x - 3), that is (x + 1) and (x - 3)

y = a(x + 1)(x - 3)

to find a substitute any other point that lies on the graph into the equation.

using (0, - 3 )

- 3 = a(0 + 1)(0 - 3) = a(1)(- 3) = - 3a ( divide both sides by - 3 )

1 = a

y = (x + 1)(x - 3) ← in factored form

3 0
2 years ago
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