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uranmaximum [27]
2 years ago
7

J/4 - 1 = 1.7 solve for j ​

Mathematics
1 answer:
Andrew [12]2 years ago
3 0

Answer:

j=10.8

Step-by-step explanation:

First, you want to get rid of that 1, so to do that, you add 1 to each side, so you have j/4=2.7. Next, to get rid of the division, you need to multiply by 4 instead, so if you multiply each side by 4 to cancel out the division, you're left with j=10.8

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Janine is saving money to buy a car. She has a total of $1400 left to save, and she plans to save a certain percentage of $1400
shusha [124]

Answer:

August=$350

September=$560

October=$210

November= $280

Step-by-step explanation:

Total amount left to save $1400.

We calculate the amount save each mount since we are already given the percentages.

For the month of August she saves 25% of $1400, we convert the percentage to equivalent cash

\frac{25}{100}*1400\\=350

for the month of August, she saved $350,

Next For the month of September she saves 40% of $1400, we convert the percentage to equivalent cash

\frac{40}{100}*1400\\=560

for the month of September, she saved $560,

Next For the month of October she saves 15% of $1400, we convert the percentage to equivalent cash

\frac{15}{100}*1400\\=210

for the month of October, she saved $210,

total amount saved by October = $350+$560+$210=$1120

Amount saved by November=1400-1120=$280

5 0
3 years ago
Which of the tables represents a function?
Vanyuwa [196]
The answer is table D as it is the only one without a repeated input ❤️ hope that helps
7 0
3 years ago
Read 2 more answers
Find the missing measure
uranmaximum [27]

Answer:

x=79*

Step-by-step explanation:

136+60+85+x=360

281+x=360

x=360-281

x=79

8 0
3 years ago
Read 2 more answers
Evaluate the following double integral: xy dA D where the region D is the triangular region whose vertices are (0, 0), (0, 3), (
natulia [17]

Answer:

I= 84

Step-by-step explanation:

for

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{}_{} \int\limits^{}_D {x*y}  \, dx*dy

since D is the rectangle such that 0<x<3 , 0<y<3

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{3}_{0} \int\limits^{3}_{0} {x*y}  \, dx*dy =  \int\limits^{3}_{0} {x}  \, dx\int\limits^{3}_{0} {y}  \, dy  = x^{2} /2*y^{2} /2 =  (3^{2} /2 - 0^{2} /2)* (3^{2} /2 - 0^{2} /2) = 3^{4} /4 = 81/4

4 0
3 years ago
Y=1/4x+5<br> y=-x<br>what are the x and y values, I think I'm supposed to use substitute​
I am Lyosha [343]

Answer:

the answer are x=4y-20

and x represents the independent variable and y represents the dependent variable

5 0
3 years ago
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