What is the difference graphing sin(x)/cos(x) and sec(x)/csc(x)?
1 answer:
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The equation can be used to find the measure of ∠BAC ⇒ 2nd answer
Step-by-step explanation:
Let us revise the trigonometry ratios in the right triangle ABC, where B is the right angle, AC is the hypotenuse, AB and BC are the legs of the triangle
The trigonometry ratios of the ∠BAC, the opposite side to this angle is BC and the adjacent side to it is AB are
In Δ ABC
∵ ∠ BCA is a right angle
∴ The hypotenuse is AB
∵ The adjacent side to ∠CAB is AC
∵ The opposite side to ∠CAB is BC
∵ AB = 13 units ⇒ hypotenuse
∵ CB = 12 units ⇒ opposite
∵ AC = 5 units ⇒ adjacent
- Let us find the trigonometry ratios of angle BAC
∵ m∠CAB is x
∵
∴
∴
∵
∴
∴
∵
∴
∴
The equation can be used to find the measure of ∠BAC
Learn more:
You can learn more about the trigonometry ratios in brainly.com/question/4924817
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